Question 2 Complete the table after finding a simplified form of the difference quotient. For the function f(x) = -7x², complete the table below: f(x+h)-f(x) h x h 5 2 5 1 5 0.1 5 0.01 Hint. Find the difference quotient at x=5 first!

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Question 2**

Complete the table after finding a simplified form of the difference quotient.

For the function \( f(x) = -7x^2 \), complete the table below:

\[
\begin{array}{c|c|c}
x & h & \frac{f(x+h) - f(x)}{h} \\ \hline
5 & 2 &  \\ 
5 & 1 &  \\ 
5 & 0.1 &  \\ 
5 & 0.01 &  \\ 
\end{array}
\]

_Hint: Find the difference quotient at x=5 first!_

Options:

\[
\begin{array}{c|c|c}
x & h & \frac{f(x+h) - f(x)}{h} \\ \hline
5 & 2 & 12 \\ 
5 & 1 & 11 \\ 
5 & 0.1 & 101 \\ 
5 & 0.01 & 1001 \\ 
\end{array}
\]

\[
\begin{array}{c|c|c}
x & h & \frac{f(x+h) - f(x)}{h} \\ \hline
5 & 2 &  \\ 
5 & 1 &  \\ 
5 & 0.1 &  \\ 
5 & 0.01 &  \\ 
\end{array}
\]
Transcribed Image Text:**Technical Support** _Provide technical support for students here. Please see the sample below._ Need help using Canvas Quizzes? If so, please review the following page: [Canvas Resources for Students](#). Only registered, enrolled users can take graded quizzes. --- **Question 2** Complete the table after finding a simplified form of the difference quotient. For the function \( f(x) = -7x^2 \), complete the table below: \[ \begin{array}{c|c|c} x & h & \frac{f(x+h) - f(x)}{h} \\ \hline 5 & 2 & \\ 5 & 1 & \\ 5 & 0.1 & \\ 5 & 0.01 & \\ \end{array} \] _Hint: Find the difference quotient at x=5 first!_ Options: \[ \begin{array}{c|c|c} x & h & \frac{f(x+h) - f(x)}{h} \\ \hline 5 & 2 & 12 \\ 5 & 1 & 11 \\ 5 & 0.1 & 101 \\ 5 & 0.01 & 1001 \\ \end{array} \] \[ \begin{array}{c|c|c} x & h & \frac{f(x+h) - f(x)}{h} \\ \hline 5 & 2 & \\ 5 & 1 & \\ 5 & 0.1 & \\ 5 & 0.01 & \\ \end{array} \]
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