Population A/A A/a a/a 1 1.0 0.0 0.0 2 0.0 1.0 0.0 0.0 0.0 1.0 0.50 0.25 0.25 0.25 0.25 0.50 6 0.25 0.50 0.25 7 0.33 0.33 0.33 8 0.04 0.32 0.64 9 0.64 0.32 0.04 10 0.986049 0.013902 0.000049 4.
Consider 10 populations that have the genotype frequencies shown in the following table:
Population A/A A/a a/a
1 1.0 0.0 0.0
2 0.0 1.0 0.0
3 0.0 0.0 1.0
4 0.50 0.25 0.25
5 0.25 0.25 0.50
6 0.25 0.50 0.25
7 0.33 0.33 0.33
8 0.04 0.32 0.64
9 0.64 0.32 0.04
10 0.986049 0.013902 0.000049
a. Which of the populations are in Hardy–Weinberg
equilibrium?
b. What are p and q in each population?
c. In population 10, the A → a mutation rate is discovered to be 5 × 10
−6. What must be the fitness of the
a /a
d. In population 6, the a allele is deleterious; furthermore, the A allele is incompletely dominant; so A/A
is perfectly fit, A/a has a fitness of 0.8, and a/a has afitness of 0.6. If there is no mutation, what will p and q be
in the next generation?
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