Point out the difference between int pthread_mutex_lock ( pthread_mutex_t *mutex_lock); and int pthread_mutex_trylock ( pthread_mutex_t *mutex_lock);
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Point out the difference between
int pthread_mutex_lock (
pthread_mutex_t *mutex_lock);
and
int pthread_mutex_trylock (
pthread_mutex_t *mutex_lock);
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- Write the following C code in RISCV without using any opcode and it should be able to run through the Cornell Computer Science interper. int x[100]; for(int i = 0; i < 10; i++) {x[i] = *i; }▼ Part A - The effect of an arithmetic shift on signed numbers Let's look at see what happens to signed numbers during a shift operation. As with most problems with number representations, errors can be intermittent. Sometimes the code will work as expected, and other times it will behave in a manner that seems to be totally arbitrary. Consider the following code fragment that makes use of the fact that shifting a value left by one place multiplies the number by 2. By passing in the number to be multiplied and the power of 2 to multiply it by (for example 4 = 22) the correct answer should be passed back from the function after the results are printed for the user to examine. signed int mult_2_to_n (signed int num, int n) { signed int result; result = num << n; printf("%d multiplied by 2^%d %d\n", num, n, result); return result; } Using a signed number as the manipulated integer may cause an error in some cases. Several approaches may be used to fix the problem. Which solutions below…What is the likelihood of an error in the REpitition code, also known as the Huffman code?
- Modify the below program that the input values representingfractions are stored with denominators that are positive integers. You cannot require the user to only enter a positive denominator value; the user should not be inconvenienced by such a restriction. For example, whilst values of 1 / -2 are acceptable inputs for a fraction, the output representation should be -1 / 2. Your solution should check the denominator input; if it is negative, swap the sign of both numerator and denominator instance variables. //Import the essential package import java.util.ArrayList; import java.util.Scanner; //Define the class Fraction class Fraction { private int n, d; public Fraction() { //Initialize the values this.n = this.d = 0; } public Fraction(int n, int d) { //Initialize the variables this.n = n; this.d = d; } //Define the getter function getNum() that returns the numerator public int getNum() {…do in python programming languagethis code is not working
- 16.FIX ME: In C language Update this function to display the string of 16 bits using the following pattern: 11111 111111 11111 (5) (6) (5) */ void printbits(unsigned short wrd) { int testbit(unsigned short wrd, int bit_to_test); int i; for (i = 15; i >= 0; i--) { printf("%1d", testbit(wrd, i)); if (!(i % 4)) printf(" "); } printf("\n"); }*Code in Python A bit shift is a procedure whereby the bits in a bit string are moved to the left or to the right. For example, we can shift the bits in the string 1011 two places to the left to produce the string 1110. Note that the leftmost two bits are wrapped around to the right side of the string in this operation. Define two scripts, shiftLeft.py and shiftRight.py, that expect a bit string as an input. The script shiftLeft shifts the bits in its input one place to the left, wrapping the leftmost bit to the rightmost position. The script shiftRight performs the inverse operation. Each script prints the resulting string. An example of shiftLeft.py input and output is shown below: Enter a string of bits: Hello world! ello world!H An example of shiftRight.py input and output is shown below: Enter a string of bits: Hello world! !Hello world
- Write a function that prints the ASCII values of the char- acters using the following header: void printASCII(char ch1, char ch2, int numberPerLine) This function prints the ASCII values of characters between ch1 and ch2 with the specified number of characters per line. Write a test program that prints 6 ASCII values per line of characters from 'a' to 'm'.Language: JAVA Problem 1: Decimal to Binary Conversion Write a program that takes an integer value as an input and converts that value to its binary representation; for instance, if the user inputs 17, then the output will be 10001. Do not forget to check for valid input, which means if the user inputs a type of data other than an integer re-prompt the user to enter a valid value. The output binary number can be a string. Sample input and output: Enter an integer > a You entered an invalid type. Try again. Enter an integer > 17 10001Solution Floating point representation: It is defined as the representation of floating numbers. It includes sign bit, exponent, and mantissa bits. Based on precision it has 2 types. 1. For IEEE 754 single-precision floating-point numbers, what is the exponent of a denormalized floating-point number in decimal? Solution: In IEEE 754 single-precision, exponent bits are 8. Therefore exponent = 2 ^(n-1) -1 = 2^(8-1) -1 = 127 OPTION D 2. For IEEE 754 single-precision floating-point numbers, how many bits for mantissa? Solution: In IEEE 754 single-precision, there are 23 bits for mantissa. sign = 1 bit exponent = 8 bits mantissa = 23 bits 3. For IEEE 754 single-precision floating-point numbers, which of the following is an example of NAN? Solution: In IEEE 754 single-precision, NAN is a special value where all exponents bits are 1's and the mantissa is non zero. a. 1 111 1 111 0000 0000 1101 0000 0000 0000 Exponent is not all 1's. Not a NAN b. 0 111 1 111 1000 0000…
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