point charge 1Q is at x = 0 and 2 Q is at x = d. What is the relation between these charges if the resultant electric field intensity is zero at the following points: (a) x = d/2, (b) x = 2d; and (c) x = −d/2
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A point charge 1Q is at x = 0 and 2 Q is at x = d. What is the relation between these charges if the resultant electric field intensity is zero at the following points: (a) x = d/2, (b) x = 2d; and (c) x = −d/2?
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- Two charges one negative and one positive with strength Q1 = -3*q and Q2= +2*q (where q=7.0 nC,q=7.0*10°C) are placed 3.6m apart. Pis located x distance from Q1, and is a point where the sum of the voltage of the two charges will sum to zero. What is the magnitude and direction in x-axis of the electric field at point P due to Q1 and Q2 in units of Newton/Coulomb? +2q 3.6Point charges of 28.0 µC and 48.0 µC are placed 0.500 m apart. (a) At what point (in m) along the line connecting them is the electric field zero? m (from the smaller charge) (b) What is the magnitude (in N/C) and direction of the electric field halfway between them? magnitude ? N/C Direction: towards larger or smaller charge?The charge density of a non-uniformly charged sphere of radius 1.0 m is given as: For rs 1.0 m; p(r)= Po(1-4r/3) For r> 1.0 m; p(r)= 0, where r is in meters. What is the value of r in meters for which the electric field is maximum? 0.25 0.50 0.75 1.00 2.00 Other:
- Which expression gives the correct electric field magnitude at point P for the geometry shown in the figure? 1 2g 4περ r 1 E = b- 2 E = v2; 2q 4T€0 r2 1 r , 4 50% || b- 2 1 E = /2; 4T€0 r2 CORRECT V2 _1 2 4T€0 E = 50% P.There are two point charges q1=(7.000x10^0) µC and q2=(-3.0000x10^0) µC. q1 is located at origin (0, 0). q2 is located at (4.00x10^0) m,(5.000x10^0) m). Now we place another point charge q3 = (1.0000x10^1) µC at ((4.00x10^0) m, 0), i.e. q3 is right underneath of q2. Please calculated the X-component of the electrostatic force on q3 . Give your answer in the unit of N with 3 sf. Note: Use the sign to represent the direction, for example -2.11x10^-4 means the force is on the negative x direction.The electric field at point P is 9.3 x 1020 N/C @ 343°. What is the angle of the force experienced by a proton if it is placed at point P. Express your answer in degrees.