Please use the image below to answer these questions 1. Considering the air resistance problem. What is the acceleration altitude of 2900ft? Show all work and be sure to include units(including directions) 2. At which altitude (s) has the skydiver reached terminal velocity? How do you know? 3. At 2900 feet, the skydiver is ——. Mark all that apply a) moving upward B) speeding up C) moving downward D) slowing down.

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Please use the image below to answer these questions 1. Considering the air resistance problem. What is the acceleration altitude of 2900ft? Show all work and be sure to include units(including directions) 2. At which altitude (s) has the skydiver reached terminal velocity? How do you know? 3. At 2900 feet, the skydiver is ——. Mark all that apply a) moving upward B) speeding up C) moving downward D) slowing down.
A skydiver jumps out of a helicopter at
6000 feet above the ground. As he
descends, the force of air resistance acting
upon him continually changes. The free-
body diagrams below represent the
magnitude and direction of the two forces
acting upon the skydiver at six positions
during his fall.
MC
6000 feet
CR
C
Fguv
3000 feet
-900 N
m/s/s
Fair=1100 N
grav=900 N
m/s/s
a=
5500 feet
Fair 200 N
Fay=900 N
2900 feet
m/s/s a=
Faiz-1500 N
900 N
4500 feet
Fair= 900 N
v-900 N
1500 feet
m/s/s
Fair-900 N
gav 900 N
m/s/s a=
For each diagram (altitude) apply Newton's
second law (Fnet = m*a) to determine the
acceleration value. Be sure to note the
direction of acceleration as well. (Hint: To
determine the sky diver's mass, consider
what you have learned about the link
between gravitational force and mass.)
m/s/s
You may use 10 m/s/s as an approximation
for g (gravitational acceleration).
Transcribed Image Text:A skydiver jumps out of a helicopter at 6000 feet above the ground. As he descends, the force of air resistance acting upon him continually changes. The free- body diagrams below represent the magnitude and direction of the two forces acting upon the skydiver at six positions during his fall. MC 6000 feet CR C Fguv 3000 feet -900 N m/s/s Fair=1100 N grav=900 N m/s/s a= 5500 feet Fair 200 N Fay=900 N 2900 feet m/s/s a= Faiz-1500 N 900 N 4500 feet Fair= 900 N v-900 N 1500 feet m/s/s Fair-900 N gav 900 N m/s/s a= For each diagram (altitude) apply Newton's second law (Fnet = m*a) to determine the acceleration value. Be sure to note the direction of acceleration as well. (Hint: To determine the sky diver's mass, consider what you have learned about the link between gravitational force and mass.) m/s/s You may use 10 m/s/s as an approximation for g (gravitational acceleration).
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