If m, is a 1.0 kg mass spinning in a circle of radius 1.0 m and m, = 4 kg what is the speed of m, assuming neither mass is moving vertically and there is minimal friction between the string and tube? m,

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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format in solving: 1. given 2. diagram (simple labeled sketch) 3. solution (use formula from formula sheet) 4. therefore statement (full answer with correct sig figs)
FORMULA SHEET
Motion Equations:
Gravitational, Electric and Magnetic Fields:
d
Vave =
Vavg =
dr = d, + d2 + d3 + ……
ü = v, + ät
GMm
F =
GMm
E, =-
d, = d, + dz + dz+.
F, =
= ka
i =
+ ü)t
d = ö,t +
d = öt -
ü2 = v,? + 2äd
kog
E =
ΔΕ
AV =
V = kq
AE, =-AE
v²
a. =
q = Ne
= BIT sin 0
F = Bqü sin 0
HNI
Relative Motion:
B = ANI
Forces:
Modern Physics
Enet = må
= mỹ
F, = µFN
Fnet = F, + F2 + F,+...
Ato
At =
L = L. 1
m =
Energy and Momentum:
E = mc? – m.c?
E =
- moc²
p = mü
Ap = F At
= mAi
p = p'
Constants:
т — т,
g = 9.8 m/s² [Down]
k = 9.0 × 10° N - m² /C?
e =1.60 x 10-19C
H. = 47x10"T - m/ A
c = 3.0 x 10* m / s
v,'= v,|
т, +т,
= Amü
ElasticCollisions
G = 6.67 x 10-11 N-m²/kg²
2m,
v,'= v,
m, + m,
M, = 5.98×10ª kg
Earth
r = 6.37×10ʻm
m, =1.67×10" kg
m¸ = 9.11×10~" kg }Atom
r, = 5.29×10"m
E, -m
E. = kx?
W = F. Ad cos0
AE¸ = mgAh
Transcribed Image Text:FORMULA SHEET Motion Equations: Gravitational, Electric and Magnetic Fields: d Vave = Vavg = dr = d, + d2 + d3 + …… ü = v, + ät GMm F = GMm E, =- d, = d, + dz + dz+. F, = = ka i = + ü)t d = ö,t + d = öt - ü2 = v,? + 2äd kog E = ΔΕ AV = V = kq AE, =-AE v² a. = q = Ne = BIT sin 0 F = Bqü sin 0 HNI Relative Motion: B = ANI Forces: Modern Physics Enet = må = mỹ F, = µFN Fnet = F, + F2 + F,+... Ato At = L = L. 1 m = Energy and Momentum: E = mc? – m.c? E = - moc² p = mü Ap = F At = mAi p = p' Constants: т — т, g = 9.8 m/s² [Down] k = 9.0 × 10° N - m² /C? e =1.60 x 10-19C H. = 47x10"T - m/ A c = 3.0 x 10* m / s v,'= v,| т, +т, = Amü ElasticCollisions G = 6.67 x 10-11 N-m²/kg² 2m, v,'= v, m, + m, M, = 5.98×10ª kg Earth r = 6.37×10ʻm m, =1.67×10" kg m¸ = 9.11×10~" kg }Atom r, = 5.29×10"m E, -m E. = kx? W = F. Ad cos0 AE¸ = mgAh
If m, is a 1.0 kg mass spinning in a circle of radius 1.0 m and m, = 4 kg what is the speed
of m, assuming neither mass is moving vertically and there is minimal friction between the string
and tube?
m.
m,
Transcribed Image Text:If m, is a 1.0 kg mass spinning in a circle of radius 1.0 m and m, = 4 kg what is the speed of m, assuming neither mass is moving vertically and there is minimal friction between the string and tube? m. m,
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