please solve using double integration method O Pab 2l -b)PL3EIPL?Og =2EIPLPL?16EIPx2(3L² – 4x*) 0 sxs48EI48EI6E 3L – x)Ph(L -9/3LEIPhx(L -x - b)OSxsaPx2GLEI-(21 - a)Pab6L EIE (3a - x) 0SxsaB6EIPa?dn =AE (3L - a)Og =-PaPb (L.at xVPah6EI2EI(21 -b)6LEIPa?(3x- a) a SXSL6EIPh(31-46) if a >bSaerT48EISwl(L'- 21.x +x')Smar384EI- - AEI24EI-(6L – 4Lx+x²)OB =6EI24EISEI2L Ela - 21)² + 2a(a - 21.)x + Lx daer (S2 - 121b+ 84y241. EI(SL - 121b + 8A)384EI(a - 2L)WoOSxsa241. EIif a zbME(6a - 4ax+x) 0sxs a24EIWoa24ET AL - a) Og =-(-L+x)(a - 4Lx + 2x)SanterKET (3L - 2a) if asb 34LET (21. -a")(31 - 2a) if a sb24L. EI6EI24L. EI96EIWpa"24E (4x - a)asxsLda 0.006 522"El360EI(7L* – 102x² + 3x*)at x- 0.51931360LEISio "LSar-0.006 510EI45 EIwoLA120L ET (10L' – 10L²X+5Lx² – x³) | ôp =24EI30EIat xAMax(L-x)6LEIE19 vaMol9/3EI6EIMoLMox?SanerMoLOg =EI16EI3EIMo2EI2EI

Answered: Image /qna-images/answer/2e6eaba1-cd71-4b58-b2ee-441dfa3954a3.jpg

Answered: please solve using double integration…

Engineering

Mechanical Engineering

please solve using double integration method

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Thermodynamic Relations

Thermodynamics is the division of physics that deals with the transfer of any kind of energy, whether it be heat, temperature, or work, from one object to another.

Question

please solve using double integration method

O Pab 2l -b)
PL
3EI
PL?
Og =
2EI
PL
PL?
16EI
Px2
(3L² – 4x*) 0 sxs
48EI
48EI
6E 3L – x)
Ph(L -
9/3LEI
Phx
(L -x - b)
OSxsa
Px2
GLEI
-(21 - a)
Pab
6L EI
E (3a - x) 0Sxsa
B
6EI
Pa?
dn =AE (3L - a)
Og =-
Pa
Pb (L.
at xV
Pah
6EI
2EI
(21 -b)
6LEI
Pa?
(3x- a) a SXSL
6EI
Ph
(31-46) if a >b
SaerT
48EI
Swl
(L'- 21.x +x')
Smar
384EI
- - AEI
24EI
-(6L – 4Lx+x²)
OB =
6EI
24EI
SEI
2L Ela - 21)² + 2a(a - 21.)x + Lx daer (S2 - 121b+ 84y
241. EI
(SL - 121b + 8A)
384EI
(a - 2L)
Wo
OSxsa
241. EI
if a zb
ME(6a - 4ax+x) 0sxs a
24EI
Woa
24ET AL - a) Og =-
(-L+x)(a - 4Lx + 2x)
Santer
KET (3L - 2a) if asb 34LET (21. -a")
(31 - 2a) if a sb
24L. EI
6EI
24L. EI
96EI
Wpa"
24E (4x - a)
asxsL
da 0.006 522
"
El
360EI
(7L* – 102x² + 3x*)
at x- 0.51931
360LEI
Sio "L
Sar-0.006 510
EI
45 EI
woL
A
120L ET (10L' – 10L²X+5Lx² – x³) | ôp =
24EI
30EI
at xA
Max
(L-x)
6LEI
E19 va
Mol
9/3EI
6EI
MoL
Mox?
Saner
MoL
Og =
EI
16EI
3EI
Mo
2EI
2EI

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