Please show all solutions. And please balance using half reaction method following the steps shown in the second picture. Thank you.

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Please show all solutions. And please balance using half reaction method following the steps shown in the second picture. Thank you.

Steps in the Half-Reaction Method The balancing process begins with a "skel-
eton" ionic reaction that consists of only species that are oxidized and reduced. Here
are the steps in the half-reaction method:
Step 1. Divide the skeleton reaction into two half-reactions, each of which contains the
oxidized and reduced forms of one of the species: if the oxidized form of a species
is on the left side, the reduced form must be on the right, and vice versa.
Step 2. Balance the atoms and charges in each half-reaction.
Atoms are balanced in this order: atoms other than O and H, then O, then H.
Charge is balanced by adding electrons (e-) to the left side in the reduction
half-reaction because the reactant gains them and to the right side in the
oxidation half-reaction because the reactant loses them.
Step 3. If necessary, multiply one or both half-reactions by an integer so that
number of e gained in reduction
number of e- lost in oxidation
%3D
Step 4. Add the balanced half-reactions, and include states of matter.
Step 5. Check that the atoms and charges are balanced.
Let's balance a redox reaction that occurs in acidic solution and then see how to bal-
ance one in basic solution in Sample Problem 21.1.
Transcribed Image Text:Steps in the Half-Reaction Method The balancing process begins with a "skel- eton" ionic reaction that consists of only species that are oxidized and reduced. Here are the steps in the half-reaction method: Step 1. Divide the skeleton reaction into two half-reactions, each of which contains the oxidized and reduced forms of one of the species: if the oxidized form of a species is on the left side, the reduced form must be on the right, and vice versa. Step 2. Balance the atoms and charges in each half-reaction. Atoms are balanced in this order: atoms other than O and H, then O, then H. Charge is balanced by adding electrons (e-) to the left side in the reduction half-reaction because the reactant gains them and to the right side in the oxidation half-reaction because the reactant loses them. Step 3. If necessary, multiply one or both half-reactions by an integer so that number of e gained in reduction number of e- lost in oxidation %3D Step 4. Add the balanced half-reactions, and include states of matter. Step 5. Check that the atoms and charges are balanced. Let's balance a redox reaction that occurs in acidic solution and then see how to bal- ance one in basic solution in Sample Problem 21.1.
21.32 Balance each skeleton reaction, calculate E and state
whether the reaction is spontaneous:
(a) Cl,(g) + Fe2+(aq)
(b) Mn2 (aq) + Co(aq)
(c) AgCl(s) + NO(g)
cell
Cl(aq) + Fe (ag)
MnO,(s) + Co2 (aq) [acidic]
Ag(s) + CI (aq) + NO, (aq) [acidic]
Transcribed Image Text:21.32 Balance each skeleton reaction, calculate E and state whether the reaction is spontaneous: (a) Cl,(g) + Fe2+(aq) (b) Mn2 (aq) + Co(aq) (c) AgCl(s) + NO(g) cell Cl(aq) + Fe (ag) MnO,(s) + Co2 (aq) [acidic] Ag(s) + CI (aq) + NO, (aq) [acidic]
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