Please refer to picture. A hydraulic jack is used to lift a car in a mechanic's shop. The mechanic wants to lift a 1,200 kg car which sits on a cylinder of hydraulic fluid with a 1 m diameter. The mechanic will push down on a cylinder of hydraulic fluid with diameter 5 cm. Question A: How much force must the mechanic exert to lift the car? Please answer in newtons Question B: If the mechanic pushes the jack down 1 m. How high will the car rise? Please answer in mm. Question C: How much work does the mechanic perform on the hydraulic fluid? Please answer in joules Question D: How much work does the hydraulic fluid perform on the car? Please anwer in joules
Please refer to picture. A hydraulic jack is used to lift a car in a mechanic's shop. The mechanic wants to lift a 1,200 kg car which sits on a cylinder of hydraulic fluid with a 1 m diameter. The mechanic will push down on a cylinder of hydraulic fluid with diameter 5 cm. Question A: How much force must the mechanic exert to lift the car? Please answer in newtons Question B: If the mechanic pushes the jack down 1 m. How high will the car rise? Please answer in mm. Question C: How much work does the mechanic perform on the hydraulic fluid? Please answer in joules Question D: How much work does the hydraulic fluid perform on the car? Please anwer in joules
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Please refer to picture. A hydraulic jack is used to lift a car in a mechanic's shop. The mechanic wants to lift a 1,200 kg car which sits on a cylinder of hydraulic fluid with a 1 m diameter. The mechanic will push down on a cylinder of hydraulic fluid with diameter 5 cm.
Question A: How much force must the mechanic exert to lift the car? Please answer in newtons
Question B: If the mechanic pushes the jack down 1 m. How high will the car rise? Please answer in mm.
Question C: How much work does the mechanic perform on the hydraulic fluid? Please answer in joules
Question D: How much work does the hydraulic fluid perform on the car? Please anwer in joules

Transcribed Image Text:### Hydraulic Lift Diagram
This diagram illustrates a hydraulic lift system used to elevate a car. The lift operates on the principle of Pascal's Law, which states that a change in pressure applied to an enclosed fluid is transmitted undiminished to every point of the fluid and to the walls of its container.
#### Components:
1. **Input Section (on the left):**
- **Fin**: This represents the input force applied on a smaller piston.
- A lever or small pump is used to exert this downward force on the piston, pushing fluid through the system.
2. **Fluid Pathway:**
- The pressurized fluid moves through a connecting pipe from the smaller piston to the larger piston located underneath the car.
3. **Output Section (on the right):**
- **Fout**: This denotes the output force exerted by the larger piston, lifting the car.
- The larger piston experiences the same pressure increase but over a larger area, resulting in a greater force.
#### Key Points:
- **Force Amplification**: The system showcases how a small input force can be transformed into a much larger output force, enabling the lift to elevate heavy objects such as cars with relatively little effort.
- **Fluid Dynamics**: The incompressible fluid efficiently transmits pressure from the input to the output section, emphasizing hydraulic systems' efficiency in mechanical processes.
This hydraulic lift is a prime example of applying fluid mechanics and hydraulic principles to solve practical engineering problems, such as lifting heavy vehicles for maintenance and repair.
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