Answered: Please refer to Figure 2 included in…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Please refer to Figure 2 included in this folder. For the moment please disregard the moving charge off to the right. The diagram above shows segments of two long straight wires, carrying currents I_1 = 1.50 A and I_2 = 1.69 A respectively. The distance between the wires is 4.47 cm. What is the force on a 1.60-cm segment of wire #2 due to the magnetic field from wire #1?

Expert Solution

Step 1: The magnetic force between two parallel current-carrying wires:

The formula for the magnetic force between two parallel current-carrying wires:

$F equals fraction numerator mu subscript 0 times I subscript 1 times I subscript 2 times L over denominator 2 pi times d end fraction$

Where:
$F$ is the force,
$mu subscript 0$ is the permeability of free space ( $4 pi cross times 10 to the power of negative 7 end exponent blank text Tm/A end text$ ),
$I subscript 1$ and $I subscript 2$ are the currents in wires 1 and 2 respectively,
$L$ is the length of wire #2,
$d$ is the distance between the wires.

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