8. In a mass spectrometer a charged particle is accelerated to a velocity v = 5.9 107 m/s by an electric field and allowed to enter a magnetic field B, where it is deflected in a semi-circular path of radius R = 10 cm. The magnetic field is uniform of magnitude B = 16 T and oriented out of the page. L a. What is the sign of the charge on the particle? b. What is the acceleration of the particle in the magnetic field? C. What is the ratio between the charge and mass of the particle q/m? d. What is the direction of the accelerating electric field? e. What is the accelerating voltage of the electric field? Ositive be the fu is downwards. k=v² ma r 2 C = (5.9x107)² nl nompels edi in nonsisted to atingem oris visas's in 16 m/s 2 m = 3.481 e 16 m/ M Sup
8. In a mass spectrometer a charged particle is accelerated to a velocity v = 5.9 107 m/s by an electric field and allowed to enter a magnetic field B, where it is deflected in a semi-circular path of radius R = 10 cm. The magnetic field is uniform of magnitude B = 16 T and oriented out of the page. L a. What is the sign of the charge on the particle? b. What is the acceleration of the particle in the magnetic field? C. What is the ratio between the charge and mass of the particle q/m? d. What is the direction of the accelerating electric field? e. What is the accelerating voltage of the electric field? Ositive be the fu is downwards. k=v² ma r 2 C = (5.9x107)² nl nompels edi in nonsisted to atingem oris visas's in 16 m/s 2 m = 3.481 e 16 m/ M Sup
Related questions
Question
how would you do part c of this? this is a non graded practice worksheet
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images