Please let me know how to get S.D and p-value step by step manually!This is the link for this question: https://www.bartleby.com/questions-and-answers/12.-chris-wants-to-know-the-changes-in-the-heights-of-all-his-friends-by-comparing-their-previous-av/667ac0d9-4ada-46e0-ac56-442874ed8efc 7.5978 98)Stepla)Previous Nowdifference100104-4125130-590110-207796-1985112-27mean95.4110.4mean-15S.D10.07472084Step2b)Null hypothesis :Alternative hypothesis :Step3c)Test statistics :t =( 95.4–110.4) –8010.0747V521. 0853 7.5917.2 98Alternative hypothesis :Step3c)Test statistics :t =( 95.4–110.4) –8010.0747– 21. 0853Step4d)Level of significance = 0.05%3DP-value = 0.00002As P-value < significance levelSo, it rejects Null hypothesis.Therefore, there is sufficient evidence tosupport the claim.

Answered: Image /qna-images/answer/986015bc-d2da-4971-a9ff-688c4866023e.jpg

Answered: Please let me know how to get S.D and…

Math

Statistics

Please let me know how to get S.D and p-value step by step manually!

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

I need help with just part c. Someone on here already answered it for me but I'm really confused as there are steps missing and I'm not sure what to put in the calculator. " The first quartile separates the lowest 25% of the observations from the higher 75% of the observations. The first quartile is denoted by Q1. The second quartile separates the lower 50% of the observations from the higher 50% of the observations. The second quartile is denoted by Q2.The second quartile is same as median. The third quartile separates the lowest 75% of the observations from the higher 25% of the observations. The third quartile is denoted by Q3. The third quartile can obtained as follows...." Third Quartile is 1 somehow, and I don't understand how it is.
Jerry is considering opening a new ice cream store at a certain location on State Street in Madison. Jerry conducts some analysis and determines that a given location is acceptable only if the number of pedestrians passing the potential location averages more than 100 per hour. To check if this location is acceptable, Jerry records the number of pedestrians observed for each of 40 hours. Jerry finds that the average number of pedestrians that pass the potential location during each of the 40 hours he was observing, is 105.7 per hour. Jerry assumes that he knows the population standard deviation to be 16. Can Jerry conclude at the 1% significance level that the potential location for the ice cream store is acceptable? a. What is the correct set of hypotheses? Answer: Ho: u = 100 and H1: u> 100 v b. Determine the p-value Answer: 0.0122 c. Interpret the results Answer: There is not enough evidence d. Jerry is concerned with committing a Type II error. Determine the probability of Type II…
For some data, we know the range R of the data is 12 and its median is 6. Find Estimated Lowest Number, and Estimated Highest Number for this data. Give you answers in the same order asked.
The line of best fit through a set of data is y = -23.849 + 0.834x According to this equation, what is the predicted value of the dependent variable when the independent variable has value 10? y = decimal place. Round to 1
Please help
From the scatterplots, which of the following is TRUE? * SCATTER PLOT A SCATTER PLOT B Scaterplat al Tast Sre vn Self Laming Time scaterpkat of lest Score vs Self Learing line Sum of squares error (SSE) plot A is smaller than plot B. Both sum of squares error (SSE) are equal. Both plots total sum of squares (SST) are equal. The total sum of squares (SST) plot A is larger than plot B If r? is positive, then the coefficient of correlation cannot be negative. TRUE FALSE Tent Sane
What is an example of something going on in your mind or body that is automatically controlled by math or has a math equation that goes with it?
The box plots below show how fast cars are travelling at a specific time of a day on highway I-5 and l-405 in King county. Fill in the blank. I-405 I-5 45 50 55 60 65 70 75 Speed (miles per hour) If Jay is driving at the median speed on l-5, he is driving faster than % of drivers on l-405.
need answer and all the work
Students in 5 different 2nd grade classes are timed to see how long it takes to correctly answer 50 addition and subtraction problems. Each class was then taught a different strategy for basic arithmetic for one month. After the month, the students were again timed to see how long it takes to correctly answer 50 similar problems. The dot plots below show the differences in times for the students (difference after before) for each of the five classes. Which dot plot appears to indicate an improvement in time for the class? A B C D 3 -4 000 · goods goxxcomm 0 ... 8.00 88 888 8 8 8 8 。 8 88 000 0 80 800 -2 0 8 01 cooo 2 08 우 O O +-000 8 08...8.... 0 800 6 8 00 10 12
Several states have argued that the 65-mph speed limit has no justification and have refused to enforce it. The federal Department of Transportation (DOT) believes that the 65-mph limit saves lives. To illustrate its contention, the department regressed the number of traffic fatalities (Y) last year in a state on the state’s population (X1), the number of days of snow cover (X2), and the average speed of all cars (X3). The results are shown below. Table 10: Model Summary Model R R Square Adjusted R Square Std. Error of the Estimate 1 .821 a .780 .613 3.258 a. Predictors: (Constant), population, days of snow, average speed Table 11: Coefficients Coefficientsa Model Unstandardized Coefficients Standardized Coefficients t Sig. B Std. Error Beta 1 (Constant) 1.4 2.957 .473 .584 Population .00029 .00003 .0034 9.667 .000 Days of Snow 2.4 .62 .759 3.871 .000 Average Speed 10.3 1.1…
Please help needed on this asap. Thanks so much! It has been observed that some persons who suffer colitis, again suffer colitis within one year of the first episode. This is due, in part, to damage from the first episode. The performance of a new drug designed to prevent a second episode is to be tested for its effectiveness in preventing a second episode. In order to do this two groups of people suffering a first episode are selected. There are 170 people in the first group and this group will be administered the new drug. There are 132 people in the second group and this group wil be administered a placebo. After one year, 14% of the first group has a second episode and 18% of the second group has a second episode. What is a 90% confidence interval for the difference in true proportion of the two groups.