Please help me find the value of k' p= -1.41 q= -0.2 Substitution of p and q into rate law. Use the values of p and q (from Part C) and the rate law, rate = ∆(mol I2)/∆t = k ́ [I–]p [H2 O2 ]q, to determine k ́ for the solutions.
Please help me find the value of k' p= -1.41 q= -0.2 Substitution of p and q into rate law. Use the values of p and q (from Part C) and the rate law, rate = ∆(mol I2)/∆t = k ́ [I–]p [H2 O2 ]q, to determine k ́ for the solutions.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please help me find the value of k'
p= -1.41
q= -0.2
Substitution of p and q into rate law. Use the values of p and q (from Part C) and the rate law, rate = ∆(mol I2)/∆t = k ́ [I–]p [H2 O2 ]q, to determine k ́ for the solutions.
Transcribed Image Text:Table 1: A. Determination of Reaction Times
Molar Concentration of Na2s203
Volume of Na2S203 (L)
Ambient Temperature (°C)
Molar Concentration of KI
Molar Concentration of H2O2
Total Volume of Kinetic Trials (mL)
0.02
0.001
26
0.3
0.1
10
![Table 2: B. Calculations for Determining the Rate Law
Trial 6
Trial 2
Trial 4
Kinetic Trial
Time for Color Change, At (sec)
72
25
72
Moles of S203² Consumed (mol)
2.00E-05
2.00E-05
2.00E-05
A(mol 13) Produced
A(mol I;) /At (mol/s)
log (A(mol I3)/At)
Volume KI (mL)
1.00E-05
1.00E-05
1.00E-05
1.38E-07
8.00E-08
1.38E-07
-6.857
-7.097
-6.857
4
1
[11. (mol/L)**
log [1].
Volume H202 (mL)
0.06
0.3
0.3
-1.2
-0.52
-0.52
3
1.5
[H202], (mol/L)**
log [H2O2],
0.3
0.1
0.1
-1.52
-1
-1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6ffcae09-aa93-4006-b426-86514542bb71%2F24e628be-4b56-4aad-910d-b876048bf556%2Ffbq3djd_processed.png&w=3840&q=75)
Transcribed Image Text:Table 2: B. Calculations for Determining the Rate Law
Trial 6
Trial 2
Trial 4
Kinetic Trial
Time for Color Change, At (sec)
72
25
72
Moles of S203² Consumed (mol)
2.00E-05
2.00E-05
2.00E-05
A(mol 13) Produced
A(mol I;) /At (mol/s)
log (A(mol I3)/At)
Volume KI (mL)
1.00E-05
1.00E-05
1.00E-05
1.38E-07
8.00E-08
1.38E-07
-6.857
-7.097
-6.857
4
1
[11. (mol/L)**
log [1].
Volume H202 (mL)
0.06
0.3
0.3
-1.2
-0.52
-0.52
3
1.5
[H202], (mol/L)**
log [H2O2],
0.3
0.1
0.1
-1.52
-1
-1
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