Please explain the solution and analysis in detail? For intance, what is id? Why id=-id? What is 250Vbe? Why 250*Vbe? Independent and dependent source? How to solve the question? etc...
Please explain the solution and analysis in detail? For intance, what is id? Why id=-id? What is 250Vbe? Why 250*Vbe? Independent and dependent source? How to solve the question? etc...
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Question
Please explain the solution and analysis in detail?
For intance, what is id?
Why id=-id?
What is 250Vbe?
Why 250*Vbe?
Independent and dependent source?
How to solve the question?
etc...
![### Circuit Analysis
In the circuit shown, we analyze the current and power characteristics involving a voltage-controlled current source.
#### Circuit Diagram Description:
- There is a 5 mV voltage source connected in series with the dependent current source denoted as \( 250v_{be} \).
- A resistor of 8 Ω is situated in series with the voltage source and dependent current source.
- The current \( i \) flows through the resistor and is marked with an arrow to indicate direction.
#### Analysis:
- **Dependent Current Calculation:**
The current through the dependent source \( i_d \) is calculated as:
\[
i_d = 250 \times v_{be} = 250 \times (5 \, \text{mV}) = 1250 \, \text{mA} = 1.25 \, \text{A}
\]
- **Current Direction Adjustment:**
The current \( i \) through the circuit is the negative of \( i_d \) (due to direction):
\[
i = -i_d = -1.25 \, \text{A}
\]
- **Voltage Across Resistor:**
The voltage \( v \) across the 8 Ω resistor is given by:
\[
v = i \times R = -1.25 \times 8 = -10 \, \text{V}
\]
- **Power Calculation:**
The power \( p \) dissipated in the resistor is:
\[
Power, \, p = v \times i = 12.5 \, \text{W} \quad \text{(all from the dependent source)}
\]
This power is entirely supplied by the dependent source and dissipated as heat in the 8 Ω resistor.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd1da7c4d-4e7c-4d93-850d-d41f99bc457d%2F68f99e18-ef5a-45b1-9c56-0b43e3053559%2F78ygasa_processed.png&w=3840&q=75)
Transcribed Image Text:### Circuit Analysis
In the circuit shown, we analyze the current and power characteristics involving a voltage-controlled current source.
#### Circuit Diagram Description:
- There is a 5 mV voltage source connected in series with the dependent current source denoted as \( 250v_{be} \).
- A resistor of 8 Ω is situated in series with the voltage source and dependent current source.
- The current \( i \) flows through the resistor and is marked with an arrow to indicate direction.
#### Analysis:
- **Dependent Current Calculation:**
The current through the dependent source \( i_d \) is calculated as:
\[
i_d = 250 \times v_{be} = 250 \times (5 \, \text{mV}) = 1250 \, \text{mA} = 1.25 \, \text{A}
\]
- **Current Direction Adjustment:**
The current \( i \) through the circuit is the negative of \( i_d \) (due to direction):
\[
i = -i_d = -1.25 \, \text{A}
\]
- **Voltage Across Resistor:**
The voltage \( v \) across the 8 Ω resistor is given by:
\[
v = i \times R = -1.25 \times 8 = -10 \, \text{V}
\]
- **Power Calculation:**
The power \( p \) dissipated in the resistor is:
\[
Power, \, p = v \times i = 12.5 \, \text{W} \quad \text{(all from the dependent source)}
\]
This power is entirely supplied by the dependent source and dissipated as heat in the 8 Ω resistor.
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