merge :: Ord a => [a] -> [a] -> [a] merge xs [] = xs merge [] ys = ys merge (x:xs) (y:ys) | x <= y = x : merge xs (y:ys) | otherwise = y merge (x:xs) ys
merge :: Ord a => [a] -> [a] -> [a] merge xs [] = xs merge [] ys = ys merge (x:xs) (y:ys) | x <= y = x : merge xs (y:ys) | otherwise = y merge (x:xs) ys
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Please can someone explain xs and ys and these Haskell statements I can’t understand
![2. Define a recursive function
merge Ord a => [a] -> [a] -> [a]
that merges two sorted lists of values to give a single sorted list.
For example:
> merge [2,5,6] [1,3,4]
[1,2,3,4,5,6]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F16847622-3098-4315-9488-1f6f1d8bd875%2Fafd89075-4212-4c01-af48-2be1827e9cc7%2Fcllt6ki_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. Define a recursive function
merge Ord a => [a] -> [a] -> [a]
that merges two sorted lists of values to give a single sorted list.
For example:
> merge [2,5,6] [1,3,4]
[1,2,3,4,5,6]
![merge :: Ord a => [a] -> [a] -> [a]
merge xs [] = XS
merge [] ys = ys
merge (x:xs) (y:ys)
| x <= y = x : merge xs (y:ys)
| otherwise = y merge (x:xs) ys](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F16847622-3098-4315-9488-1f6f1d8bd875%2Fafd89075-4212-4c01-af48-2be1827e9cc7%2Fl86izsh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:merge :: Ord a => [a] -> [a] -> [a]
merge xs [] = XS
merge [] ys = ys
merge (x:xs) (y:ys)
| x <= y = x : merge xs (y:ys)
| otherwise = y merge (x:xs) ys
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