### Educational Content on Pinworm Infestation Treatment**Text Transcription:**Pinworm infestation, commonly found in children, can be treated with a drug that is effective in 92% of cases. Suppose that three children with pinworm infestation are given the drug. Complete parts (a) through (d) below.Supposing a success \( s \) is that the child is cured, the success probability \( p \) is 0.92.**Options:**A. Each trial consists of observing whether the child is cured of the pinworm infestation by the drug and has two possible outcomes, either cured or not cured. The results are dependent on other results. Supposing a success is \( s \) that the child is cured, the success probability \( p \) is \(\_\_\_).B. Each trial consists of observing whether the child is cured of the pinworm infestation by the drug and has three possible outcomes, which are cured, not cured, or partially cured. The results are independent. Supposing a success \( s \) is that the child is cured, the success probability \( p \) is \(\_\_\_).C. Each trial consists of observing whether the child is not cured of the pinworm infestation by the drug and has two possible outcomes, either not cured or cured. The results are independent. Supposing a success is \( s \) that the child is not cured, the success probability \( p \) is \(\_\_\_).D. Each trial consists of observing whether the child is cured of the pinworm infestation by the drug and has two possible outcomes, either cured or not cured. The results are independent. Supposing a success is \( s \) that the child is cured, the success probability \( p \) is 0.92.### Construct a table that gives the probability for each outcome.(Let \( s \) be a success and \( f \) be a failure.)| Outcome | Probability ||---------|-------------|| sss | || ssf | || sfs | || sff | || fss | || fsf | || ffs | || fff | |*(Round to three decimal places as needed.)*### Explanation of Table:The table presents the different possible outcomes for the three children treated with the drug, where "s

Supposing a success s is that the child is cured, the success probability p is 0.92 P(Success) =…

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A new screening test for Lyme disease is developed for use in the general population. The sensitivity and specificity of the new test are 60% and 70%, respectively. Five hundred people are screened at a clinic during the first year the new test is implemented. Assume the true prevalence of Lyme disease among clinic attendees is 10%. Calculate the predictive value of a positive test.
The contingency table shows the results of a random sample of patients from musculoskeletal injuries treated with acetaminophen or ibuprofen. At a=0.10, can you conclude that the treatment is related to the result? Result acetaminophen Ibuprofen Significant improvement 58 81 Slight improvement 42 19
Confidence in banks: A poll conducted in 2012 asked a random sample of 1217 adults in the United States how much confidence they had in banks and other financial institutions. A total of 160 adults said that they had a great deal of confidence. An economist claims that greater than 11% of U.S. adults have a great deal of confidence in banks. Can you conclude that the economist's claim is true? Use both =α0.05 and =α0.10 levels of significance and the P-value method with the TI-84 Plus calculator. (a) State the appropriate null and alternate hypotheses. :H0 :H1
Green Tea and Prostate Cancer A preliminary study suggests a benefit from green tea for those at risk of prostate cancer. The study involved 60 men with PIN lesions, some of which turn into prostate cancer. Half the men, randomly determined, were given 600 mg a day of a green tea extract while the other half were given a placebo. The study was double-blind, and the results after one year are shown in the table below. Treatment Cancer No Cancer Green Tea 1 29 Placebo 9 21 (a) Test at a 5% significant level to see if the sample provide evidence that taking green tea extract reduces the risk of developing prostate cancer. (b) Find 98% confidence interval for the difference between two population proportions of men with PIN lesions who get prostate cancer after taking green tea extract and after taking placebo for a year. Interpret the C.I. result.
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College students and STDs: A recent report estimated that 25% of all college students in the United States have a sexually transmitted disease (STD). Due to the demographics of the community, the director of the campus health center believes that the proportion of students who have a STD is higher at his college. He tests H0: p = 0.25 versus Ha: p > 0.25. The campus health center staff select a random sample of 150 students and determine that 43 have been diagnosed with a STD. Conduct a hypothesis test to address the director’s hypothesis. Use a 5% significance level to make your decision. Use the applet to determine the P‑value. Click here to open the applet. Which of the following is an appropriate conclusion based on the results? The data provides strong evidence that the proportion of students at his college who have a STD is more than 25%. The data suggests that the proportion of students at his college who have a STD is 29%. Of the students surveyed at his college, 29%…
A random selection of volunteers at a research institute have been exposed to a typical cold virus. After they started to have cold symptoms, 15 of them were given multivitamin tablets formulated to fight cold symptoms. The remaining 15 volunteers were given placebo tablets. For each individual, the length of time taken to recover from the cold is recorded. At the end of the experiment the following data are obtained. Days to recover from a cold Treated with multivitamin Treated with placebo 3.0, 5.6, 1.5, 6.8, 3.8, 7.5, 5.8, 4.6, 2.4, 5.0, 7.5, 5.0, 2.6, 1.7, 6.7 4.9, 6.1, 4.9, 4.2, 3.4, 5.5, 5.6, 3.4, 7.9, 6.8, 4.8, 4.2, 5.7, 2.2, 4.0 Send data to Excel Send data to calculator It is known that the population standard deviation of recovery time from a cold is 1.8 days when treated with multivitamin tablets, and the population standard deviation of recovery time from a cold is 1.5 days when treated with placebo tablets. It is also known that both populations are approximately normally…
I need help with a stat problem, section 7.2 and 7.3, thank you (please help with TI-84 commands) You receive a brochure from a large university. The brochure indicates that the mean class size for full-time faculty is fewer than 32 students. You want to test this claim. You randomly select 18 classes taught by full-time faculty and determine the class size of each. The results are shown in the table below. At α=0.10, can you support the university's claim? Complete parts (a) through (d) below. Assume the population is normally distributed. 38 29 29 31 30 41 25 23 30 27 31 33 36 31 29 32 27 23 (a) write the claim mathematically and identify Ho and Ha. (b) use technology to find the P-value. P= _____________(round to 3 decimal places) (c) decide whether to reject or fail to reject the null hypothesis. Which of the following is correct? A. reject Ho because the P value is less than the significance level. B. reject Ho because the P value is greater…
USE THE 8-STEP HYPOTHESIS TESTING Refer to the study by Carter et al. [A-9], who investigated the effect of age at onset of bipolar disorder on the course of the illness. One of the variables studied was subjects' family history. Table 3.4.1 shows the frequency of a family history of mood disorders in the two groups of interest: early age at onset (18 years or younger) and later age at onset (later than 18 years). Family History of Mood Disorders Early ≤ 18(E) 28 19 41 53 Later > 18 (L) 35 38 44 60 141 Total 63 57 85 113 Negative (A) Bipolar disorder (B) Unipolar (C) Unipolar and bipolar (D) Total 177 318 Source: Tasha D. Carter, Emanuela Mundo, Sagar V. Parkh, and James L. Kennedy, "Early Age at Onset as a Risk Factor for Poor Outcome of Bipolar Disorder," Journal of Psychiatric Research, 37 (2003), 297-303. Can we conclude on the basis of these data that subjects 18 or younger differ from subjects older than 18 with respect to family histories of mood disorders? Let a = .05.
Spam: A researcher reported that 71.8% of all email sent in a recent month was spam. A system manager at a large corporation believes that the percentage at his company may be 70%. He examines a random sample of 500 emails received at an email server, and finds that 374 of the messages are spam. Can you conclude that the percentage of emails that are spam is greater than 70% ? Use both a=0.10 and a=0.01 levels of significance and the P-value method with the TI-84 Plus calculator. Part: 0/ 4 Part 1 of 4 State the appropriate null and alterņate hypotheses. do O

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