evicardThe use of both alcohol and tobacco by high school senibrs has declined inthe last 30 years. Alcohol use is down from 68.2% to 43.1%, and the use ofcigarettes by high school seniors has decreased from 36.7% to 20.4%. Arandom sample of 300 high school seniors from a large city indicated that 54had smoked a cigarette during the 30 days prior to the survey. At the a =0.05 level of significance is this lower than the national average?

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Answered: eviclara rs has declined in 1%, and the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A runner states that his average time for running a mile is 6.5 minutes. Given the following times from 8 recent mile runs, test the claim that his actual average is not what he states it to be at the a = 0.05 level of significance. 6.25 6.6 6.8 7.2 6.3 7.0 6.5 6.75
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The scores on the Wechsler Adult Intelligence Scale are approximately Normal, with ?=100 and ?=15 . The score needed to be among the highest 10% of all scores is closest to:
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Arsenic is toxic to humans and people can be exposed to it through contaminated drinking water, food, dust, and soil. Scientists have devised a non-invasive way to measure a person's level of arsenic poisoning: by examining toenail clippings. In a recent study, scientists measure the level of arsenic (in mg/kg) in toenail clippings of 8 people who lived near a former arsenic mine in Great Britain. The following levels are recorded. 0.8, 1.9, 2.7, 3.4, 3.9, 7.1, 11.9, 26.0 Below are the summary statistics of the data. min Q1 median Q3 max sd n mean 0.8 2.5 3.65 8.3 26 7.2125 8.368041 8 Suppose the 8 people examined were randomly sampled from residents near the former arsenic mine. Is it legitimate to construct a 95% confidence interval for the mean level of arsenic (in mg/kg) in toenail clippings for residents near the former arsenic mine using a t-distribution? Explain briefly.
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eviclara rs has declined in 1%, and the use of 7% to 20.4%. A ity indicated that 54 urvey. At the a = average?