Problem 2: A proton orbits a long charged wire, making N = 1.0 x 106 revolutions per second. The radius of the orbit is R = 1.0 cm (see Fig.2). What is the wire's linear charge density? a) For such motion to be possible, should the charge on the wire be positive or negative? In Fig.2, draw the electric field created by the wire. b) Express the centripetal acceleration of the proton in terms of its orbital pa- rameters R and N. J² R mp, e FIG. 2: The scheme for Problem 2 c) Express the acceleration of the proton in terms of the electric field acting on it. You need to use the formula for the field of an infinite charged wire. 3 d) Equating the two expressions for the proton's acceleration, deduce the absolute value of the linear charge density on the wire, [2].
I need help with A,B, C and D with this problem because my professor doesn't want to help me and I keep getting the wrong answer I was wondering if you can help me, also can you label which problem is A,B,C and D. Thank you
![Problem 2: A proton orbits a long charged wire, making N = 1.0 x 106 revolutions
per second. The radius of the orbit is R = 1.0 cm (see Fig.2). What is the wire's linear
charge density?
a) For such motion to be possible, should the charge on the wire be positive or
negative? In Fig.2, draw the electric field created by the wire.
b) Express the centripetal acceleration of the proton in terms of its orbital pa-
rameters R and N.
J²
R
mp, e
FIG. 2: The scheme for
Problem 2
c) Express the acceleration of the proton in terms of the electric field acting on it. You need to use the
formula for the field of an infinite charged wire.
3
d) Equating the two expressions for the proton's acceleration, deduce the absolute value of the linear
charge density on the wire, [2].](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F18a6ec25-19be-4cf6-877e-2d16ba872e0d%2F0ff1ab3b-a330-4808-94a7-220280bf1e10%2F7krsohk_processed.png&w=3840&q=75)
Given that
Number of revolutions N = 1.0 × 106per second.
Radius of orbit R = 1.0 cm = 0.01m
(a). Since the charge on line should be negative because if I would be positive then electric force on photon would be in away from the wire and there would be no centripetal force and motion would not be possible. Hence charge on wire should be negative.
When it attracts proton then proton start motion towards the wire but it also start to produce the magnetic field and due to magnetic field it start revolution.
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