(d) What was the dust speck's final kinetic energy if it was initially moving at a speed of 6.18 m/s? K₁ = J (e) So, how fast was it after crossing the potential differene? m/s Vf=

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Chapter1: Units, Trigonometry. And Vectors
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Part d, e please and check if the answer a,b,c is correct

A charged dust speck with mass, m = 2.2 g, loses 28 mJ of kinetic energy as it moves aross an electric potential, AV = -118 V.
(a) How much work was done on the dust speck?
Wnet = -28
mJ
(b) What was the change in the dust speck's electric potential energy change, assuming that Wnet = WE?
AU = 28
(c) Find the charge on the dust speck.
28e-3
-118
Q=
mJ
V₁ =
-237
(d) What was the dust speck's final kinetic energy if it was initially moving at a speed of 6.18 m/s?
K₁=
J
μC
(e) So, how fast was it after crossing the potential differene?
m/s
Transcribed Image Text:A charged dust speck with mass, m = 2.2 g, loses 28 mJ of kinetic energy as it moves aross an electric potential, AV = -118 V. (a) How much work was done on the dust speck? Wnet = -28 mJ (b) What was the change in the dust speck's electric potential energy change, assuming that Wnet = WE? AU = 28 (c) Find the charge on the dust speck. 28e-3 -118 Q= mJ V₁ = -237 (d) What was the dust speck's final kinetic energy if it was initially moving at a speed of 6.18 m/s? K₁= J μC (e) So, how fast was it after crossing the potential differene? m/s
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