98. •A 20-g object is placed against the free end of a (k equal to 25 N/m) that is compressed 10 cm (Figure 6-42). Once released, the object slides 1.25 m across the tabletop and eventually lands 1.60 m from the edge of the table on the floor, as shown. Is there friction between the object and the tabletop? If there is, what is the coef- ficient of kinetic friction? The sliding distance on the tabletop includes the 10-cm compression of the spring and the tabletop is 1.00 m above the floor level. spring 1.25 m 10000 1.00 m -1.60 m-

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98. •A 20-g object is placed against the free end of a
(k equal to 25 N/m) that is compressed 10 cm (Figure
6-42). Once released, the object slides 1.25 m across the
tabletop and eventually lands 1.60 m from the edge of
the table on the floor, as shown. Is there friction between
the object and the tabletop? If there is, what is the coef-
ficient of kinetic friction? The sliding distance on the
tabletop includes the 10-cm compression of the spring
and the tabletop is 1.00 m above the floor level.
spring
1.25 m
10000
1.00 m
-1.60 m-
Transcribed Image Text:98. •A 20-g object is placed against the free end of a (k equal to 25 N/m) that is compressed 10 cm (Figure 6-42). Once released, the object slides 1.25 m across the tabletop and eventually lands 1.60 m from the edge of the table on the floor, as shown. Is there friction between the object and the tabletop? If there is, what is the coef- ficient of kinetic friction? The sliding distance on the tabletop includes the 10-cm compression of the spring and the tabletop is 1.00 m above the floor level. spring 1.25 m 10000 1.00 m -1.60 m-
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Step 1

The 20 g object is placed against the compressed spring, which is compressed by a distance of 10 cm. As this spring is compressed, it has a potential energy stored within it due to this compression.

This potential energy stored in the spring is given as

P=12kx2k=25 N/mx=10 cm=0.1mP=12×25×0.12P=0.125 J

As soon as this spring is released, it starts to slide the object along the tabletop. Once the spring is fully stretched, the potential energy stored in the spring goes to zero, and this potential energy gets converted into the kinetic energy of the moving object.

Now, if the tabletop is frictionless, then there would be no work being done against forces of friction by the moving object, and so there would be no energy dissipation. So the total energy of the object would remain constant during its entire motion

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