3. A mass m = 3.0 kg swings down on a string of length 1.2 m. The initial angle of the string is 45 degrees. At its lowest point it strikes and attached itself to a mass of 5.0 kg. Both objects remaining attached slide over a horizontal surface with coefficient of friction = 0.20. How far will both blocks slide before coming to a complete stop? L=1.2 m 45° 3.0 kg 5.0 kg d = ? H= 0.20
3. A mass m = 3.0 kg swings down on a string of length 1.2 m. The initial angle of the string is 45 degrees. At its lowest point it strikes and attached itself to a mass of 5.0 kg. Both objects remaining attached slide over a horizontal surface with coefficient of friction = 0.20. How far will both blocks slide before coming to a complete stop? L=1.2 m 45° 3.0 kg 5.0 kg d = ? H= 0.20
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Transcribed Image Text:**Problem 3:**
A mass \( m = 3.0 \, \text{kg} \) swings down on a string of length \( 1.2 \, \text{m} \). The initial angle of the string is \( 45^\circ \). At its lowest point, it strikes and attaches itself to a mass of \( 5.0 \, \text{kg} \). Both objects, now attached, slide over a horizontal surface with a coefficient of friction \( \mu = 0.20 \). How far will both blocks slide before coming to a complete stop?
**Diagram Explanation:**
- A 3.0 kg mass is shown hanging and swinging on a string that is initially at a \( 45^\circ \) angle with a length labeled \( L = 1.2 \, \text{m} \).
- When it reaches the lowest point, the mass collides and attaches to a 5.0 kg block on a horizontal surface.
- Both masses slide together along the surface.
- The direction of motion is represented by an arrow pointing horizontally to the right, and the distance they slide is labeled as \( d = ? \).
- The horizontal surface has a coefficient of friction \( \mu = 0.20 \).
This problem can be solved using principles of conservation of energy and dynamics with friction.
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