6. Conceptual question: The block below slides with constant velocity under the action of an applied force as shown. Given that there is friction, which statement is true? (a) W = N,|Fapp| = |Ffriel: (b) N > W, |Fapp| = |F;ricl: (c) N > W,|Fapp| > |Ffricl· (d) N < W, |Fapp| = |Fricl: (e) N < W, |Fapp| > |Ffriel: аpp аpp (f) None of the above. Fapp 14
6. Conceptual question: The block below slides with constant velocity under the action of an applied force as shown. Given that there is friction, which statement is true? (a) W = N,|Fapp| = |Ffriel: (b) N > W, |Fapp| = |F;ricl: (c) N > W,|Fapp| > |Ffricl· (d) N < W, |Fapp| = |Fricl: (e) N < W, |Fapp| > |Ffriel: аpp аpp (f) None of the above. Fapp 14
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Conceptual Question:**
The block below slides with constant velocity under the action of an applied force as shown. Given that there is friction, which statement is true?
(a) \( W = N, |\vec{F}_{\text{app}}| = |\vec{F}_{\text{fric}}| \).
(b) \( N > W, |\vec{F}_{\text{app}}| = |\vec{F}_{\text{fric}}| \).
(c) \( N > W, |\vec{F}_{\text{app}}| > |\vec{F}_{\text{fric}}| \).
(d) \( N < W, |\vec{F}_{\text{app}}| = |\vec{F}_{\text{fric}}| \).
(e) \( N < W, |\vec{F}_{\text{app}}| > |\vec{F}_{\text{fric}}| \).
(f) None of the above.
**Diagram Explanation:**
The diagram shows a block on a horizontal surface. An applied force (\(\vec{F}_{\text{app}}\)) is directed at an angle \(\theta\) below the horizontal plane towards the block. The applied force is responsible for moving the block. The frictional force (\(\vec{F}_{\text{fric}}\)) opposes this motion.
- \(W\) represents the weight of the block.
- \(N\) represents the normal force.
- The applied force has both a horizontal component (causing motion) and a vertical component (affecting the normal force).
Since the block moves at a constant velocity, the net force along the direction of motion is zero, meaning the forces are balanced in that direction. Additionally, vertical forces are balanced due to equilibrium.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1af144b1-86f1-4bbf-876f-693f648ad264%2Fd0242670-0b39-4be8-965d-1401de86f302%2F8p9bo2s_processed.png&w=3840&q=75)
Transcribed Image Text:**Conceptual Question:**
The block below slides with constant velocity under the action of an applied force as shown. Given that there is friction, which statement is true?
(a) \( W = N, |\vec{F}_{\text{app}}| = |\vec{F}_{\text{fric}}| \).
(b) \( N > W, |\vec{F}_{\text{app}}| = |\vec{F}_{\text{fric}}| \).
(c) \( N > W, |\vec{F}_{\text{app}}| > |\vec{F}_{\text{fric}}| \).
(d) \( N < W, |\vec{F}_{\text{app}}| = |\vec{F}_{\text{fric}}| \).
(e) \( N < W, |\vec{F}_{\text{app}}| > |\vec{F}_{\text{fric}}| \).
(f) None of the above.
**Diagram Explanation:**
The diagram shows a block on a horizontal surface. An applied force (\(\vec{F}_{\text{app}}\)) is directed at an angle \(\theta\) below the horizontal plane towards the block. The applied force is responsible for moving the block. The frictional force (\(\vec{F}_{\text{fric}}\)) opposes this motion.
- \(W\) represents the weight of the block.
- \(N\) represents the normal force.
- The applied force has both a horizontal component (causing motion) and a vertical component (affecting the normal force).
Since the block moves at a constant velocity, the net force along the direction of motion is zero, meaning the forces are balanced in that direction. Additionally, vertical forces are balanced due to equilibrium.
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