6. Conceptual question: The block below slides with constant velocity under the action of an applied force as shown. Given that there is friction, which statement is true? (a) W = N,|Fapp| = |Ffriel: (b) N > W, |Fapp| = |F;ricl: (c) N > W,|Fapp| > |Ffricl· (d) N < W, |Fapp| = |Fricl: (e) N < W, |Fapp| > |Ffriel: аpp аpp (f) None of the above. Fapp 14

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**Conceptual Question:**

The block below slides with constant velocity under the action of an applied force as shown. Given that there is friction, which statement is true?

(a) \( W = N, |\vec{F}_{\text{app}}| = |\vec{F}_{\text{fric}}| \).

(b) \( N > W, |\vec{F}_{\text{app}}| = |\vec{F}_{\text{fric}}| \).

(c) \( N > W, |\vec{F}_{\text{app}}| > |\vec{F}_{\text{fric}}| \).

(d) \( N < W, |\vec{F}_{\text{app}}| = |\vec{F}_{\text{fric}}| \).

(e) \( N < W, |\vec{F}_{\text{app}}| > |\vec{F}_{\text{fric}}| \).

(f) None of the above.

**Diagram Explanation:**

The diagram shows a block on a horizontal surface. An applied force (\(\vec{F}_{\text{app}}\)) is directed at an angle \(\theta\) below the horizontal plane towards the block. The applied force is responsible for moving the block. The frictional force (\(\vec{F}_{\text{fric}}\)) opposes this motion. 

- \(W\) represents the weight of the block.
- \(N\) represents the normal force.
- The applied force has both a horizontal component (causing motion) and a vertical component (affecting the normal force).

Since the block moves at a constant velocity, the net force along the direction of motion is zero, meaning the forces are balanced in that direction. Additionally, vertical forces are balanced due to equilibrium.
Transcribed Image Text:**Conceptual Question:** The block below slides with constant velocity under the action of an applied force as shown. Given that there is friction, which statement is true? (a) \( W = N, |\vec{F}_{\text{app}}| = |\vec{F}_{\text{fric}}| \). (b) \( N > W, |\vec{F}_{\text{app}}| = |\vec{F}_{\text{fric}}| \). (c) \( N > W, |\vec{F}_{\text{app}}| > |\vec{F}_{\text{fric}}| \). (d) \( N < W, |\vec{F}_{\text{app}}| = |\vec{F}_{\text{fric}}| \). (e) \( N < W, |\vec{F}_{\text{app}}| > |\vec{F}_{\text{fric}}| \). (f) None of the above. **Diagram Explanation:** The diagram shows a block on a horizontal surface. An applied force (\(\vec{F}_{\text{app}}\)) is directed at an angle \(\theta\) below the horizontal plane towards the block. The applied force is responsible for moving the block. The frictional force (\(\vec{F}_{\text{fric}}\)) opposes this motion. - \(W\) represents the weight of the block. - \(N\) represents the normal force. - The applied force has both a horizontal component (causing motion) and a vertical component (affecting the normal force). Since the block moves at a constant velocity, the net force along the direction of motion is zero, meaning the forces are balanced in that direction. Additionally, vertical forces are balanced due to equilibrium.
Expert Solution
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Let the mass of block = m Velocity of block = Constant Applied force = Fapp

 

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