Phthalonitrile (CHN) is produced by the ammoxidation of o-xylene (CH) according to the following reaction: CH (1) + O₂(g) + NH₂(g) →→ C₂H₂N₂(s) + H₂O(l) How many moles of water would be produced by the complete ammoxidation of 130.0 grams of o-xylene? 1 4
Phthalonitrile (CHN) is produced by the ammoxidation of o-xylene (CH) according to the following reaction: CH (1) + O₂(g) + NH₂(g) →→ C₂H₂N₂(s) + H₂O(l) How many moles of water would be produced by the complete ammoxidation of 130.0 grams of o-xylene? 1 4
Chemistry
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Phthalonitrile (CHN) is produced by the ammoxidation of o-xylene
(C₂H₁) according to the following reaction:
8
C₂H₁(1) + O₂(g) + NH₂(g) → C₂H₂N₂(s) + H₂O(l)
8
10
8 4
How many moles of water would be produced by the complete
ammoxidation of 130.0 grams of o-xylene?
2
F2
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30
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5
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Question 12 of 17
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Transcribed Image Text:Aktiv Chemistry
← → C
tab
shift
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esc
caps lock
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Aktiv Chemistry
40%
Phthalonitrile (CHN) is produced by the ammoxidation of o-xylene
(C₂H₁) according to the following reaction:
8
C₂H₁(1) + O₂(g) + NH₂(g) → C₂H₂N₂(s) + H₂O(l)
8
10
8 4
How many moles of water would be produced by the complete
ammoxidation of 130.0 grams of o-xylene?
2
F2
N
W
S
#3
20
F3
E
X
30
$
4
X +
D
8888
F4
R
C
LO LO
%
5
F
F5
T
Question 12 of 17
V
G
Y
7
F7
H
B
U
00
DII
F8
J
F9
K
4
N M
+/-
1
7
70
I
F10
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