phase, KV, 50 Hz, 900 km long line is operating with VS =VR = V = 1.0 p.u. and 8 = 60°. A SVC is planned to be connected at the midpoint of the line to increase power transfer capability. The control range correspond to 8 = 90°. 1) Find the limits of SVC susceptance Byc if the slope (Xs) of the control characteristic is 0.05 p.u. 2) Find the limits of the reactive power drawn by SVC, 2svc which is also the reactive power V cos injected into the bus. (Data: Zn = 300 ohms, ß = 0.06' /km). 0=pl, V= 2 0 COS 2 X₁ = tan-, Vm = Vm-Xmdr. Vm = Vet +X,I₁, B₁vc == Q₁vc=-V₁vcsvc -1, " 2 V SVC

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A three phase, 400 kV, 50 Hz, 900 km long line is operating with VS =VR = V = 1.0 p.u. and
8 = 60°. A SVC is planned to be connected at the midpoint of the line to increase power transfer
capability. The control range correspond to 8=90⁰.
1) Find the limits of SVC susceptance Bsc if the slope (Xs) of the control characteristic is 0.05
SVC
p.u.
2) Find the limits of the reactive power drawn by SVC, 2svc which is also the reactive power
8
V cos
2
V₁ =
m
injected into the bus. (Data: Zn = 300 ohms, ß = 0.06°/km). 0 =ßl,
0
COS
2
-I,
0
X Th
- tan V = V-Xml. V = Vet +X,I,. Barc=
=
2svc=-V²
SVC BSvC
ref
V SVC
2 2
"
Transcribed Image Text:A three phase, 400 kV, 50 Hz, 900 km long line is operating with VS =VR = V = 1.0 p.u. and 8 = 60°. A SVC is planned to be connected at the midpoint of the line to increase power transfer capability. The control range correspond to 8=90⁰. 1) Find the limits of SVC susceptance Bsc if the slope (Xs) of the control characteristic is 0.05 SVC p.u. 2) Find the limits of the reactive power drawn by SVC, 2svc which is also the reactive power 8 V cos 2 V₁ = m injected into the bus. (Data: Zn = 300 ohms, ß = 0.06°/km). 0 =ßl, 0 COS 2 -I, 0 X Th - tan V = V-Xml. V = Vet +X,I,. Barc= = 2svc=-V² SVC BSvC ref V SVC 2 2 "
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