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400 A. d.) The impedance of the terminating device is 14.9 + j 1.5 ohms and the primary CT fault current is 1200 A w 100 80 60 40 20 8 10 0. Secondary exciting amps-, 2 4 6 Secondary exciting volts-E'

400 A. d.) The impedance of the terminating device is 14.9 + j 1.5 ohms and the primary CT fault current is 1200 A w 100 80 60 40 20 8 10 0. Secondary exciting amps-, 2 4 6 Secondary exciting volts-E'

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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4. A CT with an excitation curve given in the figure has a rated current ratio of 500:5 A and a secondary leakage impedance of 0.1 +j0.5 ohms. Calculate the CT secondary output current and the CT error for the following cases: a.) The impedance of the terminating device is 4.9 +j 0.5 ohms and the primary CT load current is 400 A. b.) The impedance of the terminating device is 4.9 +j0.5 ohms and the primary CT load current is 1200A c.) The impedance of the terminating device is 14.9 + j 1.5 ohms and the primary CT fault current is 400 A. d.) The impedance of the terminating device is 14.9 + j 1.5 ohms and the primary CT fault current is 1200 A w 100 80 60 40 20 2 4 6 10 Secondary exciting amps-, Secondary exciting volts-E'
Transcribed Image Text:4. A CT with an excitation curve given in the figure has a rated current ratio of 500:5 A and a secondary leakage impedance of 0.1 +j0.5 ohms. Calculate the CT secondary output current and the CT error for the following cases: a.) The impedance of the terminating device is 4.9 +j 0.5 ohms and the primary CT load current is 400 A. b.) The impedance of the terminating device is 4.9 +j0.5 ohms and the primary CT load current is 1200A c.) The impedance of the terminating device is 14.9 + j 1.5 ohms and the primary CT fault current is 400 A. d.) The impedance of the terminating device is 14.9 + j 1.5 ohms and the primary CT fault current is 1200 A w 100 80 60 40 20 2 4 6 10 Secondary exciting amps-, Secondary exciting volts-E'
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