perform better on the golfing test using the new method as compared to the traditional teaching technique? 1. From the output, report the test statistic and the probability (obtained p-value, called “sig” in the output). Remember to include degrees of freedom when you report t-values.  2. Will you reject or fail to reject the null based on the SPSS output (Remember to use numbers from the output only to make your statistical conclusion.

MATLAB: An Introduction with Applications
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Chapter1: Starting With Matlab
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Mr. Palmer, has been teaching beginners how to fix their stroke for the last 10 years. The mean golfing score for all past students who learned with Mr. Palmer is 79. This golfing cycle, he tried a new teaching method using simulations instead of real-world golf. He then had 15 of his students that used his new method take a golfing test. Enter the data into SPSS. Use this dataset to answer this question: did Mr. Palmer’s students perform better on the golfing test using the new method as compared to the traditional teaching technique?

1. From the output, report the test statistic and the probability (obtained p-value, called “sig” in the output). Remember to include degrees of freedom when you report t-values. 

2. Will you reject or fail to reject the null based on the SPSS output (Remember to use numbers from the output only to make your statistical conclusion.  If you use a critical t, you will get no points.).

T-Test
[DataSet0]
mid_score
N
One-Sample Statistics
15 71.0667
t
mid_score 18.907
Mean Std. Deviation
14.55760
mid_score Cohen's d
df
14
Std. Error
Mean
3.75876
One-Sample Test
Test Value =
Significance
One-Sided p Two-Sided p
<.001
<.001
One-Sample Effect Sizes
Standardizera Point Estimate
4.882
4.615
0
Mean
Difference
71.06667
95% Confidence Interval of the
95% Confidence Interval
Lower
Upper
3.018
2.853
14.55760
Hedges' correction
15.40018
a. The denominator used in estimating the effect sizes.
Cohen's d uses the sample standard deviation.
Hedges' correction uses the sample standard deviation, plus a correction factor.
Lower
63.0049
6.733
6.364
Difference
Upper
79.1284
Transcribed Image Text:T-Test [DataSet0] mid_score N One-Sample Statistics 15 71.0667 t mid_score 18.907 Mean Std. Deviation 14.55760 mid_score Cohen's d df 14 Std. Error Mean 3.75876 One-Sample Test Test Value = Significance One-Sided p Two-Sided p <.001 <.001 One-Sample Effect Sizes Standardizera Point Estimate 4.882 4.615 0 Mean Difference 71.06667 95% Confidence Interval of the 95% Confidence Interval Lower Upper 3.018 2.853 14.55760 Hedges' correction 15.40018 a. The denominator used in estimating the effect sizes. Cohen's d uses the sample standard deviation. Hedges' correction uses the sample standard deviation, plus a correction factor. Lower 63.0049 6.733 6.364 Difference Upper 79.1284
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