Perform a Two-tailed Hypothesis test TWICE, once using a *p-value approach and then again *using a critical value approach by using a format like that outlined in the screen shot above. Do all steps as shown on the screen shot using a significance level of: α = .05, and the hypotheses below: Perform an upper-tail hypothesis test TWICE, once using a *p-value approach and then again *using a critical value approach by using a format like that outlined in the screen shot above. Do all steps as shown on the screen shot using a significance level of: α = .05, and the hypotheses below:*HYPOTHESIS TESTING 2-Tail Test (p-value) Hypothesis Test (alpha = .05) State the hypothesesHo: µ = 7 H1: µ ≠ 7Find the test statistic, t State the Rejection Rule Conclusion 2-Tail Test (critical values of t = -2.023 and t = +2.023) Hypothesis Test (alpha=.05) State the hypothesesHo: µ = 7 H1: µ ≠ 7Find the test statistic, t State the Rejection Rule Conclusion Final Conclusion: Based on the context of rating London’s Heathrow Airport,what do results of the 2-tail hypothesis tests mean? Upper-Tail Test (p-value) Hypothesis Test (alpha = .05) State the hypothesesHo: µ = 7 H1: µ > 7Find the test statistic, t State the Rejection Rule Conclusion Upper-Tail Test (critical value t = 1.685) Hypothesis Test (alpha = .05) State the hypothesesHo: µ = 7 H1: µ > 7Find the test statistic, t State the Rejection Rule Conclusion Final Conclusion: Based on the context of rating London’s Heathrow Airport, what do results of the upper-tail hypothesis tests mean? F33ent FfxlA.1 Estrella Vera Chavez2.Eroothesis Test Abouta Bopulation Mcan with a unkownHYPOTHESIS TESTING5.798Lower Tall Test (pvalue) Hypothesls Test (alpha - 05)6,7046.7196390Somple SizeSample MeanSample Standbrd Devlatio40.0006.9981.004.State the Hypotheses4.67473018,447Find the Statstlc, tState the rejedlon ruleHypothesized Value7.00010Condlusion6.055)6.73871305.023Standard ErrorTest Statistic,tDegrees of Freedom(110.1590.013Lower Tall Test (critlalvaluets0987)Hypothess Test (alpha .05)39.00014State the hypthesespvalue (lowertall)pvalue{uppertall).ipvaluc(two-tall).0.5050.4958.301Find the test statistic, t1683237.080State the rejection ruleConclusion0.990(17三華014.539(20.2 Tail Test (p-value) Hypotheses Tes (alphas 05]21,6.0307.534State the Hypothes's227.258Find the te tatis24State the Rejection RuleConclusion2561156.42672732787587:4376833031327572,6.14669233478277195)71023637387864397496)698440417:30842434445

Given Information: Sample size (n) = 40 Sample mean (x¯) = 6.998 Sample standard deviation (s) = 1.004 Significance level α=0.05 Null Hypothesis: Ho: µ = 7 Alternative Hypothesis: H1: µ ≠ 7 This is a two tailed test. Since, population standard deviation is not known, use t-test. Test statistic is given by the formula: t=x¯-μ0sn Substitute the given values in the formula: t=x¯-μ0sn=6.998-71.00440=-0.0020.15875=-0.01259≈-0.013 Thus, the value of the test statistic is -0.013 Using t-distribution table, Critical values for a two tailed test at 0.05 significance level and degrees of freedom = n-1=40-1=39 are: -2.023 and +2.023 Since, computed value of the test statistic lies in between the two critical values, we fail to reject the null hypothesis. Therefore, based on context of rating London’s Heathrow Airport, the population mean is equal to 7. P-value approach: P-value is the probability of obtaining the value of the test statistic or a value more extreme, assuming the null hypothesis is true. Using Excel function "=T.DIST.2T(0.013,39)", p-value obtained is 0.989694 Decision Rule: If p-value is less than the significance level, reject the null hypothesis. If p-value is greater than the significance level, do not reject the null hypothesis. Since, p-value is greater than the significance level 0.05, do not reject the null hypothesis.Upper tail test: Null Hypothesis: Ho: µ = 7 Alternative Hypothesis: H1: µ > 7 Critical value for one tailed test at 0.05 significance level and degrees of freedom = 39 is 1.6849 ≈1.685 Rejection Rule: For a Right tailed (upper) test, reject Ho : If computed value of the test statistic is less than the critical value. Otherwise, do not reject Ho Since, computed t-value is less than the critical value 1.685, Fail to Reject the null Hypothesis. P-value: Using Excel function "=T.DIST.RT(0.013,39)", p-value obtained is 0.494847. Since, p-value is greater than the significance level 0.05, we fail to reject the null hypothesis. Based on the context of rating London’s Heathrow Airport, there is no sufficient evidence that the population mean of ratings is greater than 7.

Answered: Perform a Two-tailed Hypothesis test…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

Perform a Two-tailed Hypothesis test TWICE, once using a *p-value approach and then again *using a critical value approach by using a format like that outlined in the screen shot above. Do all steps as shown on the screen shot using a significance level of: α = .05, and the hypotheses below:

Perform an upper-tail hypothesis test TWICE, once using a *p-value approach and then again *using a critical value approach by using a format like that outlined in the screen shot above. Do all steps as shown on the screen shot using a significance level of: α = .05, and the hypotheses below:

*HYPOTHESIS TESTING

2-Tail Test (p-value) Hypothesis Test (alpha = .05)

State the hypotheses	H_o: µ = 7
	H₁: µ ≠ 7
Find the test statistic, t
State the Rejection Rule
Conclusion

2-Tail Test (critical values of t = -2.023 and t = +2.023) Hypothesis Test (alpha=.05)

State the hypotheses	H_o: µ = 7
	H₁: µ ≠ 7
Find the test statistic, t
State the Rejection Rule
Conclusion

Final Conclusion: Based on the context of rating London’s Heathrow Airport,
what do results of the 2-tail hypothesis tests mean?


Upper-Tail Test (p-value) Hypothesis Test (alpha = .05)

State the hypotheses	H_o: µ = 7
	H₁: µ > 7
Find the test statistic, t
State the Rejection Rule
Conclusion

Upper-Tail Test (critical value t = 1.685) Hypothesis Test (alpha = .05)

State the hypotheses	H_o: µ = 7
	H₁: µ > 7
Find the test statistic, t
State the Rejection Rule
Conclusion

Final Conclusion: Based on the context of rating London’s Heathrow Airport,
what do results of the upper-tail hypothesis tests mean?

F33
ent F
fxl
A.
1 Estrella Vera Chavez
2.
Eroothesis Test Abouta Bopulation Mcan with a unkown
HYPOTHESIS TESTING
5.798
Lower Tall Test (pvalue) Hypothesls Test (alpha - 05)
6,704
6.719
6390
Somple Size
Sample Mean
Sample Standbrd Devlatio
40.000
6.998
1.004.
State the Hypotheses
4.674
7301
8,447
Find the Statstlc, t
State the rejedlon rule
Hypothesized Value
7.000
10
Condlusion
6.055)
6.738
7130
5.023
Standard Error
Test Statistic,t
Degrees of Freedom
(11
0.159
0.013
Lower Tall Test (critlalvaluets0987)Hypothess Test (alpha .05)
39.000
14
State the hyptheses
pvalue (lowertall)
pvalue{uppertall).
ipvaluc(two-tall).
0.505
0.495
8.301
Find the test statistic, t
16
8323
7.080
State the rejection rule
Conclusion
0.990
(17
三華01
4.539
(20.
2 Tail Test (p-value) Hypotheses Tes (alphas 05]
21,
6.030
7.534
State the Hypothes's
22
7.258
Find the te tatis
24
State the Rejection Rule
Conclusion
25
6115
6.426
7273
27
8758
7:437
683
30
31
32
7572,
6.146
6923
34
7827
7195)
7102
36
37
38
7864
39
7496)
6984
40
41
7:308
42
43
44
45

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