The mean weight of super model winners is greater than 108 pounds. A study of 25 randomly selected super model resulted in a mean winner weight of 115 pounds. Choose the correct Null and Alternative Hypothesis
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- Samples of pages were randomly selected from three different novels. The Flesch Reading Ease scores were obtained from each page, and the TI-83/84 Plus calculator results from analysis of variance are given below. Use a 0.05 significance level to test the claim that the three books have the same mean Flesch Reading Ease score. iClick the icon to view the TI-83/84 Plus calculator results. What is the conclusion for this hypothesis test? C O A. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the three books have the same mean Flesch Reading Ease score. O B. Fail to reject Ho. There is sufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. Reject Ho. There is insufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. O D. Fail to reject Ho. There is insufficient evidence to warrant the rejection of the claim that the three…A private and a public university are located in the same city. For the private university, 1046 alumni were surveyed and 653 said that they attended at least one class reunion. For the public university, 791 out of 1327 sampled alumni claimed they have attended at least one class reunion. Is the difference in the sample proportions statistically significant at the 1% level? (Null and Alternate Hypothesis and Rejection Region) [Group 1: Private University; Group 2: Public University] A. Ho: p1 = p 2; Ha: p 1 < p 2; Rejection Region: z < -2.33 B. Ho: p 1 = p 2; Ha: p 1 < p 2; Rejection Region: z < -1.64 C. Ho: p 1 = p 2; Ha: p 1 > p 2; Rejection Region: z > 2.33 D. Ho: p 1 = p 2; Ha: p 1 ≠ p 2; Rejection Region: z < -2.58 or z > 2.58 E. Ho: p 1 = p 2; Ha: p 1 ≠ p 2; Rejection Region: t < -3.02 or t > 3.02 (Test Statistic) A. z = 1.372 B. z = 1.398 C. z = 69.517 D. z = 1.400 E. z = 6.508 (p-value and conclusion) A. p = 0.919; RHo (Sufficient evidence…Samples of pages were randomly selected from three different novels. The Flesch Reading Ease scores were obtained from each page, and the TI-83/84 Plus calculator results from analysis of variance are given below. Use a 0.01 significance level to test the claim that the three books have the same mean Flesch Reading Ease score. i Click the icon to view the TI-83/84 Plus calculator results. What is the conclusion for this hypothesis test? C O A. Fail to reject Ho. There is sufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. OB. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the three books have the same mean Flesch Reading Ease score. O C. Reject Ho. There is insufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. O D. Fail to reject Ho. There is insufficient evidence to warrant the rejection of the claim that the…
- A random sample of 817 births included 428 boys. Use a 0.05 significance level to test the claim that 50.6% of newborn babies are boys. Do the results support the belief that 50.6% of newborn babies are boys? Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test isA researcher wanted to examine whether type of dog food (freeze dried meat vs generic brand kibble) would affect dogs’ attention span. The researcher hypothesized that dogs who ate freeze dried meat would have longer attention spans than those who ate generic brand kibble. The researcher used a single sample of 13 subjects, that took part in both treatment conditions. Should the researcher use a one-tailed or two-tailed test? one-tailed two-tailedIn Malaysia legal system, a defendant is presumed innocent until proven guilty. Consider a null hypothesis, H0, that a defendant is innocent, and an alternative hypothesis, H1, that the defendant is guilty. A jury has two possible decisions: Convict the defendant (reject the null hypothesis) or do not convict the defendant (do not reject the null hypothesis). Explain the meanings of the risks of committing either a Type I or Type II error in this sample.
- A researcher wants to know if mood is affected by music. She conducts a test on a sample of 4 randomly selected adults and measures mood rating before and after being exposed to classic rock music. Test the hypothesis that mood rating decreased after being exposed to classic rock music. The mood ratings for the four participants are provided. Assume that all conditions for testing have been met. Report the null and alternative hypothesis and p-value. At the 1% significance level, state the decision regarding the null hypothesis and the conclusion about the original claim. Round all values to the nearest thousandth. Click the icon to view the mood ratings. OA. Ho Hdifference =0, Ha Hdifference >0; p=0.373; Reject the null hypothesis; there is strong evidence to suggest that exposure to classic rock music decreased mood rating. B. Ho Hdifference =0, Ha Hdifference >0; p=0.373; Fail to reject the null hypothesis; there is not strong evidence to suggest that exposure to classic rock music…In a study of red/green color blindness, 800 men and 2050 women are randomly selected and tested. Among the men, 68 have red/green color blindness. Among the women, 5 have red/green color blindness. We wish to test the claim that men have a higher rate of red/green color blindness. The test statistic is?The p-value is?A study was done to provide data on sleep deprivation rates of Californians and Oregonians. The percent of California residents who reported insufficient rest or sleep during each of the preceding 30 days is 8.0%, while this percent is 8.8% for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. a) Conduct a hypothesis test to determine if these data provide strong evidence the rate of sleep deprivation is different for the two states. Use California as Group A and Oregon as Group B. Round your test statistic to 2 decimal places and your p-value to 4 decimal places. Test statistic: p-value: Conclusion:
- In one study of smokers who tried to quit smoking with nicotine patch therapy, 40 were smoking one year after treatment and 32 were not smoking one year after the treatment. Use a 0.05 significance level to test the claim that among smokers who try to quit with nicotine patch therapy, the majority are smoking one year after the treatment. Do these results suggest that the nicotine patch therapy is not effective? Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is Identify the P-value for this hypothesis test. The P-value for this hypothesis test isA large manufacturing company claims that less than 10% of its customers make a complaint about the company’s products. Test this claim at the 10% significance level, if a survey found that 29 out of a random sample of 320 of the company’s customers made a complaint about the company’s products.