The mean weight of super model winners is greater than 108 pounds. A study of 25 randomly selected super model resulted in a mean winner weight of 115 pounds. Choose the correct Null and Alternative Hypothesis
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- Samples of pages were randomly selected from three different novels. The Flesch Reading Ease scores were obtained from each page, and the TI-83/84 Plus calculator results from analysis of variance are given below. Use a 0.01 significance level to test the claim that the three books have the same mean Flesch Reading Ease score. i Click the icon to view the TI-83/84 Plus calculator results. What is the conclusion for this hypothesis test? C O A. Fail to reject Ho. There is sufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. OB. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the three books have the same mean Flesch Reading Ease score. O C. Reject Ho. There is insufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. O D. Fail to reject Ho. There is insufficient evidence to warrant the rejection of the claim that the…A random sample of 817 births included 428 boys. Use a 0.05 significance level to test the claim that 50.6% of newborn babies are boys. Do the results support the belief that 50.6% of newborn babies are boys? Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test isA regional planner obtains random samples of home costs from four Michigan counties. Suppose these home costs are normally distributed in each county and that home prices within each county vary about the same amount. What test should the planner use to learn if the differences in home cost by county are significant? State the null and alternative hypothesis Provide the name of the hypothesis testing method and explain why it is appropriate.
- A researcher wanted to examine whether type of dog food (freeze dried meat vs generic brand kibble) would affect dogs’ attention span. The researcher hypothesized that dogs who ate freeze dried meat would have longer attention spans than those who ate generic brand kibble. The researcher used a single sample of 13 subjects, that took part in both treatment conditions. Should the researcher use a one-tailed or two-tailed test? one-tailed two-tailedTwo different simple random samples are drawn from two different populations. The first sample consists of 40 people with 22 having a common attribute. The second sample consists of 1900 people with 1375 of them having the same common attribute.compare results from a hypothesis test of p1-=p2 with a 0.05 significance level and a 95% confidence interval estimate of p1-p2 .A researcher wants to know if mood is affected by music. She conducts a test on a sample of 4 randomly selected adults and measures mood rating before and after being exposed to classic rock music. Test the hypothesis that mood rating decreased after being exposed to classic rock music. The mood ratings for the four participants are provided. Assume that all conditions for testing have been met. Report the null and alternative hypothesis and p-value. At the 1% significance level, state the decision regarding the null hypothesis and the conclusion about the original claim. Round all values to the nearest thousandth. Click the icon to view the mood ratings. OA. Ho Hdifference =0, Ha Hdifference >0; p=0.373; Reject the null hypothesis; there is strong evidence to suggest that exposure to classic rock music decreased mood rating. B. Ho Hdifference =0, Ha Hdifference >0; p=0.373; Fail to reject the null hypothesis; there is not strong evidence to suggest that exposure to classic rock music…
- The jobless rate for Italy in January 2015 was 13.4%. In a random sample of 50 employable adults in one city, 8 were unemployed. Check with the Assumptions/Conditions apply. The samples are randomly selected. The trials are independent. There are at least 10 chances to success and 10 chances to fail. The sample size represents less that 10% of the population.A study was done to provide data on sleep deprivation rates of Californians and Oregonians. The percent of California residents who reported insufficient rest or sleep during each of the preceding 30 days is 8.0%, while this percent is 8.8% for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. a) Conduct a hypothesis test to determine if these data provide strong evidence the rate of sleep deprivation is different for the two states. Use California as Group A and Oregon as Group B. Round your test statistic to 2 decimal places and your p-value to 4 decimal places. Test statistic: p-value: Conclusion:PLEASE ONLY SELECT THE ANSWERS AS SHOWN FOR THE MULTIPLE CHOICE, SUCH AS OPTION 1, 2, ETC. 1) A genetic experiment involving peas yielded one sample of offspring consisting of 427 green peas and 127 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 25% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? A. H0: p=0.25 H1: p<0.25 B. H0: p=0.25 H1: p>0.25 C. H0: p≠0.25 H1: p=0.25 D. H0: p=0.25 H1: p≠0.25 E. H0: p≠0.25 H1: p<0.25 F. H0: p≠0.25 H1: p>0.25 2) What is the test statistic? Z= (Round to two decimal places as needed.) 3) What is the P-value? P-value= (Round to four decimal places as needed.) 4) What is the…
- Use the two-proportions z-test to perform the required hypothesis test. Assume that independent simple random samples have been selected from the two populations. A marketing survey involves product recognition in New York and California. Of 558 New Yorkers surveyed, 193 recognized the product while 196 out of 614 Californians recognized the product. At the 5% significance level, do the data provide sufficient evidence to conclude that the recognition rate in New York differs from the recognition rate in California?A survey will be conducted to compare the grade point averages of US high-school students from four different school districts. Students are to be randomly selected from each of the four districts and their grade point averages recorded. The ANOVA model most likely to fit this situation is: O oneway ANOVA based on independent samples. O two-way ANOVA based on independent samples. O one-way ANOVA based on randomised blocks. O random effects ANOVA
