A poll of 1047 U.S. adults split the sample into four age groups: ages 18-29, 30-49, 50-64, and 65+. In the youngest agegroup, 59% said that they thought the U.S. was ready for a woman president, as opposed to 38% who said "no, the countrywas not ready" (3% were undecided). The sample included 262 18- to 29-year olds.a) Do you expect the 90% confidence interval for the true proportion of all 18- to 29-year olds who think the U.S. is ready fora woman president to be wider or narrower than the 90% confidence interval for the true proportion of all U.S. adults?b) Construct a 90% confidence interval for the true proportion of all 18- to 29-year olds who believe the U.S. is ready for awoman president.a) The 90% confidence interval for the true proportion of 18- to 29-year olds who think the U.S. is ready for a womanpresident will be abouttwiceas wide as the 90% confidence interval for the true proportion of all U.S. adults whothink this.b) The 90% confidence interval is ( %. %).(Round to one decimal place as needed.)

Answered: Image /qna-images/answer/126cf196-dca2-4ec4-a533-833af4ceebd8.jpg

Answered: ]%]%). (Round to one decimal place as…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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1. The t value with a 95% confidence and 24 degrees of freedom is 2.492 1.711 2.069 2.064
How often do you go out dancing? This question was asked by a professional survey group on behalf of the National Arts Survey. A random sample of n1 = 95 single men showed that r1 = 23 went out dancing occasionally. Another random sample of n2 = 92 single women showed that r2 = 19 went out dancing occasionally. Note: For degrees of freedom d.f. not in the Student's t table, use the closest d.f. that is smaller. In some situations, this choice of d.f. may increase the P-value a small amount and thereby produce a slightly more "conservative" answer. (a) Do these data indicate that the proportion of single men who go out dancing occasionally is higher than the proportion of single women who do so? Use a 5% level of significance. List the assumptions you made in solving this problem. Do you think these assumptions are realistic? What is the level of significance? What is the value of the sample test statistic? (Round your answer to three decimal places.) (b) Compute a 90% confidence…
I just need help with parts D and E please.
The NIH is creating a test for the Zika virus. The incidence of a Zika is low, 11 percent in the general population. There is a trial version, but it sometimes misses the disease. The probability of a false negative is 0.03. Similarly, someone who does not have Zika, will sometimes get a positive reading. The probability of this is 0.1. Fill in the tree diagram and... Answer as a decimal to 4 decimal places. D = event that someone actually has Zika %3D positive = event that a test states that a person has Zika Conditional Marginal Probabilities Joint Probabilities Probabilities 0.9700 Enter an integer or decimal number [more..] P(D and positive) P(positive | D) False 0.1100 0.0300 negative P(D) P(negative | D) P(D and negative) 0.1000 False Positive 0.8900 P(no D) P(positive | no D) P(no D and positive) 0.9000 P(negative | no D) P(no D and negative)
Answer Part B
Please answer all. Thank you. The width of a confidence interval for a proportion will be A.) wider for sample of size 100 than for a sample size of 50 B.) wider when the sample proportion is 0.50 than when the sample proportion is 0.20 C.) wider for 90 percent confidence than for 95 percent D.) narrower for 99 percent confidence than for 95 percent Which of the following is not a property of a normally distributed data. A.) the mean, median and mode coincide at the center B.) area under curve is 1 C.) the width of curve is determined by the mean of distribution. D.) the curve is symmetrical about its center.
In a survey of 2002 adults in a recent year, 702 made a New Year's resolution to eat healthier. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. The 90% confidence interval for the population proportion p is ,. (Round to three decimal places as needed.) The 95% confidence interval for the population proportion p is ,. (Round to three decimal places as needed.) With the given confidence, it can be said that the ▼ population proportion sample proportion of adults who say they have made a New Year's resolution to eat healthier is ▼ greater than the lower endpoint not between the endpoints less than the upper endpoint between the endpoints of the given confidence interval. Compare the widths of the confidence intervals. Choose the correct answer below. A. The 90% confidence interval is wider. B. The 95% confidence interval is wider.…
Illustration 18.1. The measured proport:on of success in a samplè of 25 is 0.5. (a) what is a 99% confidence interval for n? (b) what should be the sample size for width of this interval to be 0.02? be 0.02?
In a poll, 69% of the people polled answered yes to the question "Are you in favor of the death penalty for a person convicted of murder?" The margin of error in the poll was 2%, and the estimate was made with 96% confidence. At least how many people were surveyed?

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]%]%). (Round to one decimal place as needed.) b) The 90% confidence interval is