Determine the margin of error for a confidence interval to estimate the population mean with n= 25 and s = 12.3 for the confidence levels below. a) 80% b) 90% c) 99% a) The margin of error for an 80% confidence interval is (Round to two decimal places as needed.)
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- Construct the confidence interval for the population mean p. c= 0.95, x= 5.7, o = 0.5, and n= 57 ... A 95% confidence interval for µ is ( D (Round to two decimal places as needed.)Construct the confidence interval for the population mean u. c= 0.95, x= 6.1, o = 0.6, and n = 40 A 95% confidence interval for u is ( D. (Round to two decimal places as needed.)A consumer group reports that a 90% confidence interval for the mean fat content of chicken nuggets from a fast-food restaurant is (14, 18). What is the mean fat content for the sample of 30 chicken nuggets or the point estimate that help make this confidence interval? A. 32 B. 16 C. 2
- As part of a water quality survey, you test the water hardness in several randomly selected streams. The results are shown below. Construct a confidence interval for the population variance sigma squared and the population standard deviation sigma. Use a 90% level of confidence. Assume that the population has a normal distribution. n = 23s = 18 grains per gallon a) The confidence interval for the population variance sigma squared is: b) The confidence interval for the population standard deviation sigma is:A research center survey of 2,484 adults found that 1,942 had bought something online. Of these online shoppers, 1,295 are weekly online shoppers. Complete parts (a) through (c) below. a. Construct a 95% confidence interval estimate of the population proportion of adults who had bought something online. Sas (Round to four decimal places as needed.) led b. Construct a 95% confidence interval estimate of the population proportion of online shoppers who are weekly online shoppers. Sas (Round to four decimal places as needed.) c. How would the director of e-commerce sales for a company use the results of (a) and (b)? O A. Since a greater proportion of adults have purchased something online than are weekly online shoppers, the director of e-commerce sales may want to focus on those adults who have purchased something online. led O B. The information cannot be compared because it is derived from two different opinions. O C. Agreater proportion of adults have purchased something online, but…Two intervals are given, A and B, for the same value of the explanatory variable. A: 11 to 17; B: 8 to 20; (a) Which interval is the confidence interval for the mean response?A or B Which interval is the prediction interval for the response?A or B (b) What is the predicted value of the response variable for this value of the explanatory variable?Enter the exact answer.The predicted value is=
- Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the confidence level. Round the margin of error to four decimal placesAbout 25 randomly selected people were asked how long they slept at night. The mean time was 6 hours, and the standard deviation was 1 hour. Calculate the 98% confidence interval of the mean time by assuming that the variable is normally distributed. Provide only the value required below. Express your answer in 3 decimal places. a. tą (positive value only):Please answer all. Thank you. The width of a confidence interval for a proportion will be A.) wider for sample of size 100 than for a sample size of 50 B.) wider when the sample proportion is 0.50 than when the sample proportion is 0.20 C.) wider for 90 percent confidence than for 95 percent D.) narrower for 99 percent confidence than for 95 percent Which of the following is not a property of a normally distributed data. A.) the mean, median and mode coincide at the center B.) area under curve is 1 C.) the width of curve is determined by the mean of distribution. D.) the curve is symmetrical about its center.
- How many adults should be involved in this study in order to have the mean age estimated up to ±6 months with 92% and 98% confidence levels?Construct the confidence interval for the population mean μ. c= 0.90, x= 16.7, o = 2.0, and n = 60 A 90% confidence interval for u is . (Round to one decimal place as needed.)Construct a confidence interval for p, - p2 at the given level of confidence. X1 = 35, n, = 254, x2 = 31, n2 = 300, 90% confidence %3D ... The researchers are % confident the difference between the two population proportions, p, - P2, is between and (Use ascending order. Type an integer or decimal rounded to three decimal places as needed.)
