A survey of 31 men found that the standard deviation is 3.1 and the average number of social media accounts men have is 12.3. Another survey of 37 women found that standard deviation is 3.7 and the average number of social media accounts women have is 12.3. Find the 80% confidence interval of the difference of two means?
A survey of 31 men found that the standard deviation is 3.1 and the average number of social media accounts men have is 12.3. Another survey of 37 women found that standard deviation is 3.7 and the average number of social media accounts women have is 12.3. Find the 80% confidence interval of the difference of two means?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A survey of 31 men found that the standard deviation is 3.1 and the average number of social media accounts men have is 12.3. Another survey of 37 women found that standard deviation is 3.7 and the average number of social media accounts women have is 12.3. Find the 80% confidence interval of the difference of two means?

Transcribed Image Text:a) Which formula will you use for this problem?
- \( \hat{p} - z_{\alpha/2} \cdot \sqrt{\frac{\hat{p} \cdot \hat{q}}{n}} < p < \hat{p} + z_{\alpha/2} \cdot \sqrt{\frac{\hat{p} \cdot \hat{q}}{n}} \)
- \( \bar{x} - t_{\alpha/2} \cdot \frac{s}{\sqrt{n}} < \mu < \bar{x} + t_{\alpha/2} \cdot \frac{s}{\sqrt{n}} \)
- \( (\hat{p}_1 - \hat{p}_2) - z_{\alpha/2} \cdot \sqrt{\frac{\hat{p}_1 \cdot \hat{q}_1}{n_1} + \frac{\hat{p}_2 \cdot \hat{q}_2}{n_2}} < p_1 - p_2 < (\hat{p}_1 - \hat{p}_2) + z_{\alpha/2} \cdot \sqrt{\frac{\hat{p}_1 \cdot \hat{q}_1}{n_1} + \frac{\hat{p}_2 \cdot \hat{q}_2}{n_2}} \)
- \( (\bar{x}_1 - \bar{x}_2) - t_{\alpha/2} \cdot \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}} < \mu_1 - \mu_2 < (\bar{x}_1 - \bar{x}_2) + t_{\alpha/2} \cdot \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}} \)
- \( n = \left(-\frac{z_{\alpha/2} \cdot \sigma}{E}\right)^2 \)
- \( \bar{x} - z_{\alpha/2} \cdot \frac{\sigma}{\sqrt{n}} < \mu < \bar{x} + z_{\alpha/2} \cdot \frac{\sigma}{\sqrt{n}} \)
- \( n = \

Transcribed Image Text:The image provides a series of inputs for a statistical calculation, likely related to computing a confidence interval. Here is a transcription of the text and instructions:
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c) Find the values of each component of our formula. Then, use that information to find the confidence interval.
**Write the exact value for each**
1. \(\text{?} = \_\_\_\_\) (Women's Sample Mean)
2. \(\text{?} = \_\_\_\_\) (Men's Sample Mean)
3. \(\text{?} = \_\_\_\_\)
4. \(\text{?} = \_\_\_\_\)
5. \(\text{?} = \_\_\_\_\) (Sample Size Women)
6. \(\text{?} = \_\_\_\_\) (Sample Size Men)
**Round to Two Decimal Places**
7. \(\text{?} = \_\_\_\_\) (\(\alpha / 2\))
**Round answer(s) to two decimal places (no commas)**
Select an answer
---
There are no graphs or diagrams in the image. The inputs are for entering numerical data relevant to statistical analysis, particularly confidence intervals, involving sample means and sizes for men and women.
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