A random sample of 30 words from Jane Austen's Pride and Prejudice had a mean length of 4.08 letters with a standard deviation of 2.40. A random sample of 30 words from Henry James's What Maisie Knew had a mean length of 3.85 letters with a standard deviation of 2.26. Which of the following is a correct expression for the 99% confidence interval for the difference in mean word length for these two novels? (a) (4.08– 3.85) ± 2.756 2.40, 2.26 V30 /30 (b) (4.08 – 3.85)±2.045| V30 2.40 2.26 + 30 2.402 2.262 + 30 |2.402 2.262 (c) (4.08 – 3.85)± 2.045 30 (d) (4.08 – 3.85)±2.045 30 30 |2.40² 2.26? (e) (4.08 – 3.85)±2.756| 30 30

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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A random sample of 30 words from Jane Austen's Pride and Prejudice had a mean length of 4.08 letters with a
standard deviation of 2.40. A random sample of 30 words from Henry James's What Maisie Knew had a mean length
of 3.85 letters with a standard deviation of 2.26. Which of the following is a correct expression for the 99%
confidence interval for the difference in mean word length for these two novels?
2.40, 2.26
2.40, 2.26
(a) (4.08– 3.85)±2.756|
(b) (4.08 – 3.85) ±2.045
30 30
30 30
2.402 2.26?
|2.40?
2.26?
(c) (4.08 – 3.85)± 2.045|
30
(d) (4.08 – 3.85)±2.045
30
30
30
|2.40²
+
30
2.262
(e) (4.08 – 3.85)±2.756|
30
Transcribed Image Text:A random sample of 30 words from Jane Austen's Pride and Prejudice had a mean length of 4.08 letters with a standard deviation of 2.40. A random sample of 30 words from Henry James's What Maisie Knew had a mean length of 3.85 letters with a standard deviation of 2.26. Which of the following is a correct expression for the 99% confidence interval for the difference in mean word length for these two novels? 2.40, 2.26 2.40, 2.26 (a) (4.08– 3.85)±2.756| (b) (4.08 – 3.85) ±2.045 30 30 30 30 2.402 2.26? |2.40? 2.26? (c) (4.08 – 3.85)± 2.045| 30 (d) (4.08 – 3.85)±2.045 30 30 30 |2.40² + 30 2.262 (e) (4.08 – 3.85)±2.756| 30
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