% yield = actual yield / theoretical yield x 100 (amounts can all be in mol or all in g) Cu2CO3 (OH)2 Cuo H20 CO2 + + and calculations nce the reaction first Mass (g ) Crucible ( empty) 48.11 Sample 1.00 Crucible ( after heating ) 48.81 Cuo ( actual in g) CuzCOз (ОН)2 molar mass Cuo molar mass Mol Cuo produced ( actual in mol ) Mol sample used
% yield = actual yield / theoretical yield x 100 (amounts can all be in mol or all in g) Cu2CO3 (OH)2 Cuo H20 CO2 + + and calculations nce the reaction first Mass (g ) Crucible ( empty) 48.11 Sample 1.00 Crucible ( after heating ) 48.81 Cuo ( actual in g) CuzCOз (ОН)2 molar mass Cuo molar mass Mol Cuo produced ( actual in mol ) Mol sample used
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:% yield = actual yield / theoretical yield x 100 (amounts can all be in mol or all in g)
Cu2CO3 (OH)2
Cuo
H20
+
CO2
+
and calculations
nce the reaction first
Mass (g )
Crucible ( empty)
48.11
Sample
1.00
Crucible ( after heating )
48.81
Cuo ( actual in g)
CuzCOз (ОН)2
molar mass
Cuo molar mass
Mol Cuo produced
( actual in mol )
Mol sample used
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