Per Capita Income of Delaware Residents In a recent year, Delaware had the highest per capita annual income with $51,803. If o =$4850, answer the following questions. Assume that the sample is taken from a large population and the correction factor can be ignored. Round intermediate z-value calculations to two decimal places and the final answers to at least four decimal places. Part: 0/2 Part 1 of 2 What is the probability that a random sample of 37 state residents had a mean income greater than $50,400? P(X > 50,400) =

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**Per Capita Income of Delaware Residents**

In a recent year, Delaware had the highest per capita annual income with $51,803. If σ = $4850, answer the following questions. Assume that the sample is taken from a large population and the correction factor can be ignored. Round intermediate z-value calculations to two decimal places and the final answers to at least four decimal places.

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Part: **0 / 2**

Part 1 of 2

What is the probability that a random sample of 37 state residents had a mean income greater than $50,400?

\[ P\left( \bar{X} > 50,400 \right) = \, \boxed{} \]

[Here, a textbox and a button with an `X` and a refresh symbol are visible, likely for input and resetting the value.]
Transcribed Image Text:**Per Capita Income of Delaware Residents** In a recent year, Delaware had the highest per capita annual income with $51,803. If σ = $4850, answer the following questions. Assume that the sample is taken from a large population and the correction factor can be ignored. Round intermediate z-value calculations to two decimal places and the final answers to at least four decimal places. --- Part: **0 / 2** Part 1 of 2 What is the probability that a random sample of 37 state residents had a mean income greater than $50,400? \[ P\left( \bar{X} > 50,400 \right) = \, \boxed{} \] [Here, a textbox and a button with an `X` and a refresh symbol are visible, likely for input and resetting the value.]
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