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Particle Mass (kg) alpha particle 6.64 x 10-27 golf ball 0.0450 bullet 0.00190 Submit Answer assignment-take [Review Topics) [References) Use the References to access important values if needed for this question. Retry Entire Group Ceng Techn Velocity (m/s) Wavelength Region 1.52 x 107 31.3 313 8 more group attempts remaining Compare the de Broglie wavelength of an alpha particle moving at 3.40x107 miles per hour (1.52x107 m/s) to that of a golf ball moving at 70.0 miles per hour (31.3 m/s) and a bullet with a speed of 700 miles per hour (313 m/s). Welco bstre ultraviolet (108 to 107 m) X-ray (1011 to 108 m) gamma (10-16 to 10-¹¹m) smaller than 10-20 m Oakla 00 + 30 21 06 Update

Particle Mass (kg) alpha particle 6.64 x 10-27 golf ball 0.0450 bullet 0.00190 Submit Answer assignment-take [Review Topics) [References) Use the References to access important values if needed for this question. Retry Entire Group Ceng Techn Velocity (m/s) Wavelength Region 1.52 x 107 31.3 313 8 more group attempts remaining Compare the de Broglie wavelength of an alpha particle moving at 3.40x107 miles per hour (1.52x107 m/s) to that of a golf ball moving at 70.0 miles per hour (31.3 m/s) and a bullet with a speed of 700 miles per hour (313 m/s). Welco bstre ultraviolet (108 to 107 m) X-ray (1011 to 108 m) gamma (10-16 to 10-¹¹m) smaller than 10-20 m Oakla 00 + 30 21 06 Update

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The image displays an educational screen comparing de Broglie wavelengths of different particles. The information is organized in a table with the following headers: Particle, Mass (kg), Velocity (m/s), Wavelength, and Region. The table includes data for an alpha particle, a golf ball, and a bullet. Values provided: - **Alpha particle**: - Mass: \(6.64 \times 10^{-27}\) kg - Velocity: \(1.52 \times 10^7\) m/s - **Golf ball**: - Mass: 0.0450 kg - Velocity: 31.3 m/s - **Bullet**: - Mass: 0.00190 kg - Velocity: 313 m/s Several regions for classifying wavelengths are listed below the table: - Ultraviolet (\(10^{-8}\) to \(10^{-7}\) m) - X-ray (\(10^{-11}\) to \(10^{-8}\) m) - Gamma (\(10^{-16}\) to \(10^{-10}\) m) - Smaller than \(10^{-20}\) m The screen has buttons labeled "Submit Answer" and "Retry Entire Group." The task seems to involve calculating the de Broglie wavelengths for each particle and determining their respective regions. A set of instructions at the top guides users to compare the de Broglie wavelength of an alpha particle moving at \(3.40 \times 10^7\) miles per hour (\(1.52 \times 10^7\) m/s) to that of a golf ball moving at 70.0 miles per hour (31.3 m/s) and a bullet with a speed of 700 miles per hour (313 m/s).
Transcribed Image Text:The image displays an educational screen comparing de Broglie wavelengths of different particles. The information is organized in a table with the following headers: Particle, Mass (kg), Velocity (m/s), Wavelength, and Region. The table includes data for an alpha particle, a golf ball, and a bullet. Values provided: - **Alpha particle**: - Mass: \(6.64 \times 10^{-27}\) kg - Velocity: \(1.52 \times 10^7\) m/s - **Golf ball**: - Mass: 0.0450 kg - Velocity: 31.3 m/s - **Bullet**: - Mass: 0.00190 kg - Velocity: 313 m/s Several regions for classifying wavelengths are listed below the table: - Ultraviolet (\(10^{-8}\) to \(10^{-7}\) m) - X-ray (\(10^{-11}\) to \(10^{-8}\) m) - Gamma (\(10^{-16}\) to \(10^{-10}\) m) - Smaller than \(10^{-20}\) m The screen has buttons labeled "Submit Answer" and "Retry Entire Group." The task seems to involve calculating the de Broglie wavelengths for each particle and determining their respective regions. A set of instructions at the top guides users to compare the de Broglie wavelength of an alpha particle moving at \(3.40 \times 10^7\) miles per hour (\(1.52 \times 10^7\) m/s) to that of a golf ball moving at 70.0 miles per hour (31.3 m/s) and a bullet with a speed of 700 miles per hour (313 m/s).
**Educational Text:** --- **Topic: Comparing de Broglie Wavelengths** **Description:** This exercise involves comparing the de Broglie wavelength of different particles under specified conditions. The particles in question are a golf ball, an electron, and a proton. The goal is to identify and compare the wavelength and region for each particle based on their given velocities and masses. **Particle Information:** 1. **Golf Ball:** - **Mass:** 0.0450 kg - **Velocity:** 31.3 m/s - **Wavelength and Region:** To be calculated. 2. **Electron:** - **Mass:** \(9.11 \times 10^{-31}\) kg - **Velocity:** \(5.81 \times 10^6\) m/s - **Wavelength and Region:** To be calculated. 3. **Proton:** - **Mass:** \(1.67 \times 10^{-27}\) kg - **Velocity:** \(5.81 \times 10^6\) m/s - **Wavelength and Region:** To be calculated. **Regions Based on Wavelength:** - **Ultraviolet:** \(10^{-8}\) to \(10^{-7}\) m - **X-ray:** \(10^{-11}\) to \(10^{-10}\) m - **Gamma:** \(10^{-16}\) to \(10^{-11}\) m - **Smaller than:** \(10^{-20}\) m In this task, you will use the de Broglie wavelength formula to determine the wavelength of each particle and identify which region each wavelength corresponds to. **Additional Instructions:** - You have options to submit the answer or retry if needed. - Make sure to use any references provided for important values. **Action:** - Input your calculated values for the wavelengths in the provided table and select the corresponding wavelength region. --- **Note:** The de Broglie wavelength is an important concept in quantum mechanics and is given by the formula: \[ \lambda = \frac{h}{mv} \] where \( \lambda \) is the wavelength, \( h \) is Planck’s constant, \( m \) is the mass of the particle, and \( v \) is the velocity of the particle. Use this formula to find the precise wavelengths for each particle listed.
Transcribed Image Text:**Educational Text:** --- **Topic: Comparing de Broglie Wavelengths** **Description:** This exercise involves comparing the de Broglie wavelength of different particles under specified conditions. The particles in question are a golf ball, an electron, and a proton. The goal is to identify and compare the wavelength and region for each particle based on their given velocities and masses. **Particle Information:** 1. **Golf Ball:** - **Mass:** 0.0450 kg - **Velocity:** 31.3 m/s - **Wavelength and Region:** To be calculated. 2. **Electron:** - **Mass:** \(9.11 \times 10^{-31}\) kg - **Velocity:** \(5.81 \times 10^6\) m/s - **Wavelength and Region:** To be calculated. 3. **Proton:** - **Mass:** \(1.67 \times 10^{-27}\) kg - **Velocity:** \(5.81 \times 10^6\) m/s - **Wavelength and Region:** To be calculated. **Regions Based on Wavelength:** - **Ultraviolet:** \(10^{-8}\) to \(10^{-7}\) m - **X-ray:** \(10^{-11}\) to \(10^{-10}\) m - **Gamma:** \(10^{-16}\) to \(10^{-11}\) m - **Smaller than:** \(10^{-20}\) m In this task, you will use the de Broglie wavelength formula to determine the wavelength of each particle and identify which region each wavelength corresponds to. **Additional Instructions:** - You have options to submit the answer or retry if needed. - Make sure to use any references provided for important values. **Action:** - Input your calculated values for the wavelengths in the provided table and select the corresponding wavelength region. --- **Note:** The de Broglie wavelength is an important concept in quantum mechanics and is given by the formula: \[ \lambda = \frac{h}{mv} \] where \( \lambda \) is the wavelength, \( h \) is Planck’s constant, \( m \) is the mass of the particle, and \( v \) is the velocity of the particle. Use this formula to find the precise wavelengths for each particle listed.
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