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Question 18 of 18 What is the de Broglie wavelength (in meters) of a 455 g football when it is kicked for an extra point at a velocity of 35.3 meters per second?

Question 18 of 18 What is the de Broglie wavelength (in meters) of a 455 g football when it is kicked for an extra point at a velocity of 35.3 meters per second?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question 18 of 18** **Problem Statement:** What is the de Broglie wavelength (in meters) of a 455 g football when it is kicked for an extra point at a velocity of 35.3 meters per second? **Explanation:** The de Broglie wavelength formula is used to calculate the wavelength associated with a moving particle. It is defined as: \[ \lambda = \frac{h}{mv} \] where: - \( \lambda \) is the de Broglie wavelength, - \( h \) is Planck’s constant (\(6.626 \times 10^{-34}\) m² kg/s), - \( m \) is the mass of the object in kilograms, - \( v \) is the velocity of the object in meters per second. For this problem: - Mass \( m = 455 \) g = \( 0.455 \) kg (conversion from grams to kilograms), - Velocity \( v = 35.3 \) m/s. **Note:** To solve this, substitute the values into the formula to find the wavelength.
Transcribed Image Text:**Question 18 of 18** **Problem Statement:** What is the de Broglie wavelength (in meters) of a 455 g football when it is kicked for an extra point at a velocity of 35.3 meters per second? **Explanation:** The de Broglie wavelength formula is used to calculate the wavelength associated with a moving particle. It is defined as: \[ \lambda = \frac{h}{mv} \] where: - \( \lambda \) is the de Broglie wavelength, - \( h \) is Planck’s constant (\(6.626 \times 10^{-34}\) m² kg/s), - \( m \) is the mass of the object in kilograms, - \( v \) is the velocity of the object in meters per second. For this problem: - Mass \( m = 455 \) g = \( 0.455 \) kg (conversion from grams to kilograms), - Velocity \( v = 35.3 \) m/s. **Note:** To solve this, substitute the values into the formula to find the wavelength.
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