The final bearing capacity under vertical loading is desirable, assuming areliability coefficient of 4 and creating a total shear rupture and ageneral equationqu = c'N,FFeaFa + qN,F„FgFgi + yBN,F,FyaFyiPartвD,Foundation type28.75 kN/m? 17.29 kN/m Continuous17 kN/m16.5 kN/m Squarea.1.22 m 0.91 m 25°b.2 mIm30Continuousс.3 m2 m30°qu = c'N, + qN, + yBN,(continuous or strip foundation)qu = 1.3c'N + qNg + 0.4 BN, (square foundation)

Calculate the bearing capacity of continuous footing, qu=C'Nc+γDNq+0.5γBNγ C - Cohesion = 28.75…

Part в D, Foundation type 28.75 kN/m 17.29 kN/m Continuous 17 kN/m 16.5 kN/m a. 1.22 m 0.91 m 25° b. 2 m Im 30° Continuous с. 3 m 2 m 30° Square qu = c'N. + qN, + yBN, (continuous or strip foundation) qu = 1.3c'N. + qNg + 0.4YBN, (square foundation)

Part в D, Foundation type 28.75 kN/m 17.29 kN/m Continuous 17 kN/m 16.5 kN/m a. 1.22 m 0.91 m 25° b. 2 m Im 30° Continuous с. 3 m 2 m 30° Square qu = c'N. + qN, + yBN, (continuous or strip foundation) qu = 1.3c'N. + qNg + 0.4YBN, (square foundation)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.

Question

The final bearing capacity under vertical loading is desirable, assuming a
reliability coefficient of 4 and creating a total shear rupture and a
general equation
qu = c'N,FFeaFa + qN,F„FgFgi + yBN,F,FyaFyi
Part
в
D,
Foundation type
28.75 kN/m? 17.29 kN/m Continuous
17 kN/m
16.5 kN/m Square
a.
1.22 m 0.91 m 25°
b.
2 m
Im
30
Continuous
с.
3 m
2 m
30°
qu = c'N, + qN, + yBN,
(continuous or strip foundation)
qu = 1.3c'N + qNg + 0.4 BN, (square foundation)

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