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Part II. Balance the given REDOX reactions using the half-reaction method or ion- electron method. 1. Pb(OH)42+ CIO- → PbO2 + Cl + OH in basic solution 2. Crl3+ Cl2 → CrO42 + 104 + Cl in basic solution 3. Fe2+(aq) + MnO4 (aq)-Fe³+ (aq) + Mn²+ (aq) in basic medium Sb2O5 + HSO4 + NO in acidic solution 4. Sb2S3 + H+ + NO3 5. Cr202-7(aq) + C2H5OH(1)→ Cr3+ (aq) + CO₂(g) in acidic solution -

Part II. Balance the given REDOX reactions using the half-reaction method or ion- electron method. 1. Pb(OH)42+ CIO- → PbO2 + Cl + OH in basic solution 2. Crl3+ Cl2 → CrO42 + 104 + Cl in basic solution 3. Fe2+(aq) + MnO4 (aq)-Fe³+ (aq) + Mn²+ (aq) in basic medium Sb2O5 + HSO4 + NO in acidic solution 4. Sb2S3 + H+ + NO3 5. Cr202-7(aq) + C2H5OH(1)→ Cr3+ (aq) + CO₂(g) in acidic solution -

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please need asap. Answer number 2-5. Will upvote who will answer it all. Thanks.

Part II. Balance the given REDOX reactions using the half-reaction method or ion- electron method. 1. Pb(OH)42+CIO → PbO2 + Cl + OH in basic solution - 2. Crl3 + Cl2 → CrO42- + 104 + Cl in basic solution 3. Fe2+ (aq) + MnO4 (aq) Fe³+ (aq) + Mn²+ (aq) in basic medium 4. Sb2S3 + H+ + NO3 Sb2O5 + HSO4 + NO in acidic solution Cr202-7(aq) + C₂H5OH(1)→ Cr³+ (aq) + CO₂(g) in acidic solution 5. -
Transcribed Image Text:Part II. Balance the given REDOX reactions using the half-reaction method or ion- electron method. 1. Pb(OH)42+CIO → PbO2 + Cl + OH in basic solution - 2. Crl3 + Cl2 → CrO42- + 104 + Cl in basic solution 3. Fe2+ (aq) + MnO4 (aq) Fe³+ (aq) + Mn²+ (aq) in basic medium 4. Sb2S3 + H+ + NO3 Sb2O5 + HSO4 + NO in acidic solution Cr202-7(aq) + C₂H5OH(1)→ Cr³+ (aq) + CO₂(g) in acidic solution 5. -
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