Construct the expression for Ka for the weak acid, HC,H,04. HC,H,0,(aq) + H,0(1) = H,0*(aq) + C,H,0,"(aq) 1 Based on the definition of Ka, drag the tiles to construct the expression for the given acid. Ka = %3D
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![### Ka Expression for a Weak Acid
**Question 5 of 8**
**Problem Statement:**
Construct the expression for the acid dissociation constant (\( K_a \)) for the weak acid, \( \text{HC}_9\text{H}_7\text{O}_4 \).
#### Chemical Equation:
\[ \text{HC}_9\text{H}_7\text{O}_4\,(aq) + \text{H}_2\text{O}\,(l) \rightleftharpoons \text{H}_3\text{O}^+\,(aq) + \text{C}_9\text{H}_7\text{O}_4^-\,(aq) \]
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### Task:
Using the reaction above and the definition of \( K_a \), arrange the provided tiles to construct the expression for the equilibrium constant for the given weak acid.
#### Expression for \( K_a \):
\[ K_a = \]
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### Tiles to Use:
- \([\text{H}_2\text{O}]\)
- \([\text{H}_3\text{O}^+]\)
- \([\text{OH}^-]\)
- \([\text{HC}_9\text{H}_7\text{O}_4]\)
- \([\text{H}_2\text{C}_9\text{H}_7\text{O}_4^+]\)
- \([\text{C}_9\text{H}_7\text{O}_4^-]\)
- \(2[\text{H}_2\text{O}]\)
- \(2[\text{H}_3\text{O}^+]\)
- \(2[\text{OH}^-]\)
- \(2[\text{HC}_9\text{H}_7\text{O}_4]\)
- \([\text{H}_2\text{O}]^2\)
- \([\text{H}_3\text{O}^+]^2\)
- \([\text{OH}^-]^2\)
- \([\text{HC}_9\text{H}_7\text{O}_4]^2\)
- \([\text{H}_2\text{C}_9\text{H}_7\text{O}_4^+]^2\)
- \([\text](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdf82a722-3ffe-4d57-a846-1228f0887e42%2F4adc39fc-926c-4871-b268-f3fd8c3149f9%2F3ge3nj_processed.jpeg&w=3840&q=75)
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