PART II: A T TERBERG LIMITSPROBLEM AThe following data shows the results of the Liquid limit and Plastic limitLIQUID LIMIT TESTTEST NO.1.02.03.04.0No. of Blows (N)Mass of Wet Soil + Mass of Container (g)Mass of Dry Soi1 + Mass of Container (g)38.024.021.016.023.2420.1922.2724.1220.4419.7818.7521.10Mass of container (g)12.7413.2413.0613.27PLASTIC LIMIT TESTTEST NO.1.02.01. Determine the nearestNo. of Blows (N)Mass of Wet Soil + Mass of Container (g)Mass of Dry Soil + Mass of Container (g)value of liquid limit(LL).2. Determine the nearestvalue of plastic limit24.5222.8421.4221.5913.0713.18(PL).3. Determine the nearestvalue of plastic indexNATURAL WATER CONTENT(PI) and its soil1.02.0description.4. Determine the nearestvalue of liquid index,TEST NO.No. of Blows (N)18.5317.97(LI) and its soilMass of Wet Soil + Mass of Container (g)Mass of Dry Soil + Mass of Container (g)15.5415.56description.7.847.50

Given- Table of liquid limit and plastic limit test and natural water content

PART II: A RBERG PROBLEM A The following data shows the results of the Liquid limit and Plastic limit LIQUID LIMIT TEST TEST NO. 1.0 2.0 3.0 4.0 No. of Blows (N) 38.0 24.0 21.0 16.0 Masa of Wet Soil + Mass of Container (g) Mass of Dry Soi1 + Mass of Container (g) 23.24 20.19 22.27 24.12 20.44 19.78 18.75 21.10 Mass of container (g) 12.74 13.24 13.06 13.27 PLASTIC LIMIT TEST 1. Determine the nearest value of liquid limit (LL). TEST NO. 1.0 2.0 No. of Blows (N) 24.52 22.84 Mass of Wet Soil + Mass of Container (g) 2. Determine the nearest value of plastic limit 21.42 21.59 Masg 13.07 13. 18 (PL). Dry Sot Ma Container (a)

PART II: A RBERG PROBLEM A The following data shows the results of the Liquid limit and Plastic limit LIQUID LIMIT TEST TEST NO. 1.0 2.0 3.0 4.0 No. of Blows (N) 38.0 24.0 21.0 16.0 Masa of Wet Soil + Mass of Container (g) Mass of Dry Soi1 + Mass of Container (g) 23.24 20.19 22.27 24.12 20.44 19.78 18.75 21.10 Mass of container (g) 12.74 13.24 13.06 13.27 PLASTIC LIMIT TEST 1. Determine the nearest value of liquid limit (LL). TEST NO. 1.0 2.0 No. of Blows (N) 24.52 22.84 Mass of Wet Soil + Mass of Container (g) 2. Determine the nearest value of plastic limit 21.42 21.59 Masg 13.07 13. 18 (PL). Dry Sot Ma Container (a)

Solid Waste Engineering

3rd Edition

ISBN:9781305635203

Author:Worrell, William A.

Publisher:Worrell, William A.

Chapter5: Separation Processes

Section: Chapter Questions

Problem 5.32P

See similar textbooks

Related questions

Q: 4. Which of the following gives the plastic limit of the soil? a. 16.5 % C. 17.1 % b. 10.5 % d. 18.5…

A: First, we have to calculate the water content of the following sample then we have taken the average…

Q: The result of plastic limit determination of a soil sample is given below. Trial Mass of container…

A: The plastic limit of a soil is the moisture content at which soil begins to behave as a plastic…

Q: 1.Results from liquid and plastic limit test conducted on a soil are given below; Liquid limit test;…

Q: A 1000g of sand has been soaked for at least 24hours prior to lab. After drying the sample to…

Q: Question 33 A laboratory apparatus maintains a constant head in both the upper and lower reservoirs.…

A: Permeability of soil : The ability of soil to enable water to flow through it is referred to as…

Q: the velocity distribution for the suspension

A: Since we answer three sub-parts at a time so will answer the first three sub-parts .Please re-submit…

Concept explainers

Analysis and Procedures for Material Selection

The term material selection means to select the right material for various engineering applications. There are various engineering materials available and each has different individual properties. Thorough knowledge of the material properties and behavior is crucial in the design process. For instance, a structural member, such as a beam, is used to support vertical shear loads by the building itself. To withstand such loads, the material of the beam must possess adequate strength and stiffness to resist any deformation that might lead to the formation of cracks.

Question

100%

PART II: A T TERBERG LIMITS
PROBLEM A
The following data shows the results of the Liquid limit and Plastic limit
LIQUID LIMIT TEST
TEST NO.
1.0
2.0
3.0
4.0
No. of Blows (N)
Mass of Wet Soil + Mass of Container (g)
Mass of Dry Soi1 + Mass of Container (g)
38.0
24.0
21.0
16.0
23.24
20.19
22.27
24.12
20.44
19.78
18.75
21.10
Mass of container (g)
12.74
13.24
13.06
13.27
PLASTIC LIMIT TEST
TEST NO.
1.0
2.0
1. Determine the nearest
No. of Blows (N)
Mass of Wet Soil + Mass of Container (g)
Mass of Dry Soil + Mass of Container (g)
value of liquid limit
(LL).
2. Determine the nearest
value of plastic limit
24.52
22.84
21.42
21.59
13.07
13.18
(PL).
3. Determine the nearest
value of plastic index
NATURAL WATER CONTENT
(PI) and its soil
1.0
2.0
description.
4. Determine the nearest
value of liquid index,
TEST NO.
No. of Blows (N)
18.53
17.97
(LI) and its soil
Mass of Wet Soil + Mass of Container (g)
Mass of Dry Soil + Mass of Container (g)
15.54
15.56
description.
7.84
7.50

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Analysis and procedures for material selection

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

A hydrometer test has the following result: Gs = 2.65, temperature of water = 26 C, and L = 10.4 cm at 45 minutes after the start of sedimentation (see Figure 2.25). What is the diameter D of the smallest-size particles that have settled beyond the zone of measurement at that time (that is, t = 45 min)? Figure 2.25 ASTM 152H type of hydrometer placed inside the sedimentation cylinder (Courtesy of Khaled Sobhan, Florida Atlantic University, Boca Raton, Florida)
Three groups of students from the Geotechnical Engineering class collected soil-aggregate samples for laboratory testing from a recycled aggregate processing plant in Palm Beach County, Florida. Three samples, denoted by Soil A, Soil B, and Soil C, were collected from three locations of the aggregate stockpile, and sieve analyses were conducted (see Figure 2.35). (a) (b) Figure 2.35 (a) Soil-aggregate stockpile; (b) sieve analysis (Courtesy of Khaled Sobhan, Florida Atlantic University, Boca Raton, Florida) a. Determine the coefficient of uniformity and the coefficient of gradation for Soils A, B, and C. b. Which one is coarser: Soil A or Soil C? Justify your answer. c. Although the soils are obtained from the same stockpile, why are the curves so different? (Hint: Comment on particle segregation and representative field sampling.) d. Determine the percentages of gravel, sand and fines according to Unified Soil Classification System.
Repeat Problem 2.14 with the following values: Gs = 2.75, temperature of water = 21C, t = 88 min, and L = 11.7 cm. 2.14 A hydrometer test has the following result: Gs = 2.65, temperature of water = 26 C, and L = 10.4 cm at 45 minutes after the start of sedimentation (see Figure 2.25). What is the diameter D of the smallest-size particles that have settled beyond the zone of measurement at that time (that is, t = 45 min)? Figure 2.25 ASTM 152H type of hydrometer placed inside the sedimentation cylinder (Courtesy of Khaled Sobhan, Florida Atlantic University, Boca Raton, Florida)
Two materials, A and B, are to be separated using two unit operations, 1 and 2. The feed has 10 tons/h A and 4 tons/h B. The split (fraction of material rejected by each operation) is given in Table P5-14. a. Which sequence of operations, (l?2) or (2?1), will yield the greatest recovery of material A? b. What will be the purity of material A using that sequence? c. What will be the efficiency of separation for the entire process train with regard to material A using the Worrell-Stesed equation?
Following results are obtained for a liquid limit test using a fall cone device. Estimate the liquid limit of the soil and the flow index.
Refer to Figure 7.24. The following data were collected during the field permeability measurement of a confined aquifer using a pumping test. Determine the hydraulic conductivity of the permeable layer. Use Eq. (7.49). Thickness of the aquifer, H = 4.5 m Piezometric level and radial distance of the first observation well: h1 = 2.9 m; r1 = 17.8 m Piezometric level and radial distance of the second observation well: h2 = 1.8 m; r2 = 8.1 m Rate of discharge from pumping, q = 0.5 m3/min
Results from a liquid limit test conducted on a soil are given below. a. Determine the liquid limit of the soil. b. If it is known that the PI = 6.5, what would be the plastic limit of the soil? c. Determine the liquidity index of the soil if win situ = 23.8%