- Part C CH 59-H The product cannot be drawn because the arrow is supposed to show where the electrons move to, but there are no electrons on the H to go anywhere. O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge. O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge and a hydrogen with 2 electrons and a 1- charge. O Drawing the arrows incorrectly leads to a hydrogen with 2 electrons and a 1- charge. Submit Part D CH3 CH :Ö Request Answer Submit + HÖ:- CH3 O The product cannot be drawn because the destination of the electrons in the breaking x-bond is not clear. O Drawing the arrows incorrectly leads to an oxygen with 10 valence electrons and 2-charge and a carbon with 5 bonds and a 1+ charge. O Drawing the arrows incorrectly leads to a carbon with 5 bonds and a 1+ charge. O Drawing the arrows incorrectly leads to an oxygen with 10 valence electrons and 2- charge. Provide Feedback Request Answer
- Part C CH 59-H The product cannot be drawn because the arrow is supposed to show where the electrons move to, but there are no electrons on the H to go anywhere. O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge. O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge and a hydrogen with 2 electrons and a 1- charge. O Drawing the arrows incorrectly leads to a hydrogen with 2 electrons and a 1- charge. Submit Part D CH3 CH :Ö Request Answer Submit + HÖ:- CH3 O The product cannot be drawn because the destination of the electrons in the breaking x-bond is not clear. O Drawing the arrows incorrectly leads to an oxygen with 10 valence electrons and 2-charge and a carbon with 5 bonds and a 1+ charge. O Drawing the arrows incorrectly leads to a carbon with 5 bonds and a 1+ charge. O Drawing the arrows incorrectly leads to an oxygen with 10 valence electrons and 2- charge. Provide Feedback Request Answer
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Types of Chemical Bonds
The attractive force which has the ability of holding various constituent elements like atoms, ions, molecules, etc. together in different chemical species is termed as a chemical bond. Chemical compounds are dependent on the strength of chemical bonds between its constituents. Stronger the chemical bond, more will be the stability in the chemical compounds. Hence, it can be said that bonding defines the stability of chemical compounds.
Polarizability In Organic Chemistry
Polarizability refers to the ability of an atom/molecule to distort the electron cloud of neighboring species towards itself and the process of distortion of electron cloud is known as polarization.
Coordinate Covalent Bonds
A coordinate covalent bond is also known as a dative bond, which is a type of covalent bond. It is formed between two atoms, where the two electrons required to form the bond come from the same atom resulting in a semi-polar bond. The study of coordinate covalent bond or dative bond is important to know about the special type of bonding that leads to different properties. Since covalent compounds are non-polar whereas coordinate bonds results always in polar compounds due to charge separation.
Question
Please help with all parts
Transcribed Image Text:Part C
CH
59-H
The product cannot be drawn because the arrow is supposed to show where the electrons move to, but there are
O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge.
O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge and a hydrogen with 2 electrons and a 1- charge.
O Drawing the arrows incorrectly leads to a hydrogen with 2 electrons and a 1- charge.
Submit
Part D
CH3
CH
Request Answer
Submit
+ HÖ:-
CH3
O The product cannot be drawn because the destination of the electrons in the breaking x-bond is not clear.
O Drawing the arrows incorrectly leads to an oxygen with 10 valence electrons and 2-charge and a carbon with 5 bonds and a 1+ charge.
O Drawing the arrows incorrectly leads to a carbon with 5 bonds and a 1+ charge.
O Drawing the arrows incorrectly leads to an oxygen with 10 valence electrons and 2- charge.
Provide Feedback
electrons on the H to go anywhere.
Request Answer
Transcribed Image Text:Problem 5.5
What is wrong with the structures that you obtain using the incorrect arrows?
▼ Part A
:Ö
CH3-C
CH₂
O Drawing the arrows incorrectly leads to a bromine with an incomplete octet and a positive charge and an oxygen with 10 valence electrons and 2- charge.
O Drawing the arrows incorrectly leads to a compound with the bond between a bromine and an oxygen and an oxygen with 3 bonds.
O Drawing the arrows incorrectly leads to a bromine with an incomplete octet and a positive charge.
O The product cannot be drawn because it is not cleare if the double bond will form or oxygen will only have two more electrons and charge 3-
Submit
Part B
Request Answer
CH,Ô–H
H
O The product cannot be drawn because the arrow is supposed to show where the electrons move to, but there are no electrons on the H to go anywhere
O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge and a hydrogen with 2 electrons and a 1-charge.
O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge.
O Drawing the arrows incorrectly leads to a hydrogen with 2 electrons and a 1- charge.
Submit Request Answer
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