- Part C CH 59-H The product cannot be drawn because the arrow is supposed to show where the electrons move to, but there are no electrons on the H to go anywhere. O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge. O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge and a hydrogen with 2 electrons and a 1- charge. O Drawing the arrows incorrectly leads to a hydrogen with 2 electrons and a 1- charge. Submit Part D CH3 CH :Ö Request Answer Submit + HÖ:- CH3 O The product cannot be drawn because the destination of the electrons in the breaking x-bond is not clear. O Drawing the arrows incorrectly leads to an oxygen with 10 valence electrons and 2-charge and a carbon with 5 bonds and a 1+ charge. O Drawing the arrows incorrectly leads to a carbon with 5 bonds and a 1+ charge. O Drawing the arrows incorrectly leads to an oxygen with 10 valence electrons and 2- charge. Provide Feedback Request Answer

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Part C
CH
59-H
The product cannot be drawn because the arrow is supposed to show where the electrons move to, but there are
O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge.
O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge and a hydrogen with 2 electrons and a 1- charge.
O Drawing the arrows incorrectly leads to a hydrogen with 2 electrons and a 1- charge.
Submit
Part D
CH3
CH
Request Answer
Submit
+ HÖ:-
CH3
O The product cannot be drawn because the destination of the electrons in the breaking x-bond is not clear.
O Drawing the arrows incorrectly leads to an oxygen with 10 valence electrons and 2-charge and a carbon with 5 bonds and a 1+ charge.
O Drawing the arrows incorrectly leads to a carbon with 5 bonds and a 1+ charge.
O Drawing the arrows incorrectly leads to an oxygen with 10 valence electrons and 2- charge.
Provide Feedback
electrons on the H to go anywhere.
Request Answer
Transcribed Image Text:Part C CH 59-H The product cannot be drawn because the arrow is supposed to show where the electrons move to, but there are O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge. O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge and a hydrogen with 2 electrons and a 1- charge. O Drawing the arrows incorrectly leads to a hydrogen with 2 electrons and a 1- charge. Submit Part D CH3 CH Request Answer Submit + HÖ:- CH3 O The product cannot be drawn because the destination of the electrons in the breaking x-bond is not clear. O Drawing the arrows incorrectly leads to an oxygen with 10 valence electrons and 2-charge and a carbon with 5 bonds and a 1+ charge. O Drawing the arrows incorrectly leads to a carbon with 5 bonds and a 1+ charge. O Drawing the arrows incorrectly leads to an oxygen with 10 valence electrons and 2- charge. Provide Feedback electrons on the H to go anywhere. Request Answer
Problem 5.5
What is wrong with the structures that you obtain using the incorrect arrows?
▼ Part A
:Ö
CH3-C
CH₂
O Drawing the arrows incorrectly leads to a bromine with an incomplete octet and a positive charge and an oxygen with 10 valence electrons and 2- charge.
O Drawing the arrows incorrectly leads to a compound with the bond between a bromine and an oxygen and an oxygen with 3 bonds.
O Drawing the arrows incorrectly leads to a bromine with an incomplete octet and a positive charge.
O The product cannot be drawn because it is not cleare if the double bond will form or oxygen will only have two more electrons and charge 3-
Submit
Part B
Request Answer
CH,Ô–H
H
O The product cannot be drawn because the arrow is supposed to show where the electrons move to, but there are no electrons on the H to go anywhere
O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge and a hydrogen with 2 electrons and a 1-charge.
O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge.
O Drawing the arrows incorrectly leads to a hydrogen with 2 electrons and a 1- charge.
Submit Request Answer
Transcribed Image Text:Problem 5.5 What is wrong with the structures that you obtain using the incorrect arrows? ▼ Part A :Ö CH3-C CH₂ O Drawing the arrows incorrectly leads to a bromine with an incomplete octet and a positive charge and an oxygen with 10 valence electrons and 2- charge. O Drawing the arrows incorrectly leads to a compound with the bond between a bromine and an oxygen and an oxygen with 3 bonds. O Drawing the arrows incorrectly leads to a bromine with an incomplete octet and a positive charge. O The product cannot be drawn because it is not cleare if the double bond will form or oxygen will only have two more electrons and charge 3- Submit Part B Request Answer CH,Ô–H H O The product cannot be drawn because the arrow is supposed to show where the electrons move to, but there are no electrons on the H to go anywhere O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge and a hydrogen with 2 electrons and a 1-charge. O Drawing the arrows incorrectly leads to an oxygen with an incomplete octet and a 2+ charge. O Drawing the arrows incorrectly leads to a hydrogen with 2 electrons and a 1- charge. Submit Request Answer
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