▼ Part C ▾ Calculate the Ki, value for CH₂CH(OH)COO Express your answer numerically to two significant figures. Kb Submit Part D = Kb ΠΙΑΣΦΑ 4 Previous Answers Request Answer Calculate the K₁, value for Bro Express your answer numerically to two significant figures. = |VL]ΑΣΦ 1 ? ?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Problem 16.81 - Enhanced - with Feedback**

1. **Question:**
   - Choose between:
     - lactate ion
     - hypobromite ion

2. **Feedback:**
   - **Correct:** The relative strengths of acids and their conjugate bases are inversely related. Therefore, the stronger an acid, the weaker its conjugate base. Conversely, the weaker the acid, the stronger its conjugate base. Since lactic acid is a stronger acid than hypobromous acid, the conjugate base of lactic acid, the lactate ion, is a weaker base than the hypobromite ion (the conjugate base of hypobromous acid).

3. **Part C:**
   - Calculate the \( K_b \) value for \( \text{CH}_3\text{CH(OH)COO}^- \).
   - **Prompt:** Express your answer numerically to two significant figures.
   - Input Box for Answer:
     - \( K_b = \) [Input Field]
   - **Options:**
     - Submit
     - Previous Answers
     - Request Answer

4. **Part D:**
   - Calculate the \( K_b \) value for \( \text{BrO}^- \).
   - **Prompt:** Express your answer numerically to two significant figures.
   - Input Box for Answer:
     - \( K_b = \) [Input Field]
   - **Options:**
     - Submit
     - Previous Answers
     - Request Answer

**Note:**
There are no graphs or diagrams in this section.
Transcribed Image Text:**Problem 16.81 - Enhanced - with Feedback** 1. **Question:** - Choose between: - lactate ion - hypobromite ion 2. **Feedback:** - **Correct:** The relative strengths of acids and their conjugate bases are inversely related. Therefore, the stronger an acid, the weaker its conjugate base. Conversely, the weaker the acid, the stronger its conjugate base. Since lactic acid is a stronger acid than hypobromous acid, the conjugate base of lactic acid, the lactate ion, is a weaker base than the hypobromite ion (the conjugate base of hypobromous acid). 3. **Part C:** - Calculate the \( K_b \) value for \( \text{CH}_3\text{CH(OH)COO}^- \). - **Prompt:** Express your answer numerically to two significant figures. - Input Box for Answer: - \( K_b = \) [Input Field] - **Options:** - Submit - Previous Answers - Request Answer 4. **Part D:** - Calculate the \( K_b \) value for \( \text{BrO}^- \). - **Prompt:** Express your answer numerically to two significant figures. - Input Box for Answer: - \( K_b = \) [Input Field] - **Options:** - Submit - Previous Answers - Request Answer **Note:** There are no graphs or diagrams in this section.
Expert Solution
Step 1

The relation between Ka and Kb values are-

Ka×Kb=Kw= 1.0×10-14

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