Part C 13.0 moles of gas are in a 8.00 L tank at 23.6°C. Calculate the difference in pressure between methane and an ideal gas under these conditions. The van der Waals constants for methane are a = 2.300 L?. atm/mol and b=0.0430 L/mol. Express your answer with the appropriate units. > View Available Hint(s) HA ? pressure difference = 32.4 atm %3D

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Part c show all work
### Van der Waals Real Gas Calculation

**Problem Statement:**

Calculate the difference in pressure between methane and an ideal gas under the given conditions. 

**Given:**

- **Number of moles (n):** 13.0 moles
- **Volume (V):** 8.00 L
- **Temperature (T):** 23.6 °C
- **Van der Waals constants for methane:**
  - \( a = 2.300 \, \text{L}^2 \cdot \text{atm/mol}^2 \)
  - \( b = 0.0430 \, \text{L/mol} \)

**Task:**

Express your answer with the appropriate units.

**Attempted Solution:**

- **Pressure Difference:** 32.4 atm
- **Result:** Incorrect; 3 attempts remaining

This exercise requires calculating the pressure difference using the Van der Waals equation for real gases and comparing it with the ideal gas law result. The answer input was found to be incorrect, indicating a need to revisit the calculations.
Transcribed Image Text:### Van der Waals Real Gas Calculation **Problem Statement:** Calculate the difference in pressure between methane and an ideal gas under the given conditions. **Given:** - **Number of moles (n):** 13.0 moles - **Volume (V):** 8.00 L - **Temperature (T):** 23.6 °C - **Van der Waals constants for methane:** - \( a = 2.300 \, \text{L}^2 \cdot \text{atm/mol}^2 \) - \( b = 0.0430 \, \text{L/mol} \) **Task:** Express your answer with the appropriate units. **Attempted Solution:** - **Pressure Difference:** 32.4 atm - **Result:** Incorrect; 3 attempts remaining This exercise requires calculating the pressure difference using the Van der Waals equation for real gases and comparing it with the ideal gas law result. The answer input was found to be incorrect, indicating a need to revisit the calculations.
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Real gasses have attraction so they have less pressure than ideal gasses

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