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tor N2(9 +20219)ー> 2 (9 i, YNOLY)-> Zaiz(9) +202(4) 1. Nag +2 02 (9) -> NO2ly)

tor N2(9 +20219)ー> 2 (9 i, YNOLY)-> Zaiz(9) +202(4) 1. Nag +2 02 (9) -> NO2ly)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Heat of Combustion: Application of Hess's Law Pre-Lab** 1. Find ΔH for the reaction: \[ \text{N}_2(g) + 2\text{O}_2(g) \rightarrow 2\text{NO}_2(g) \] Given: i. \[ 4\text{NO}(g) + 2\text{O}_2(g) \rightarrow 2\text{N}_2(g) + 2\text{NO}_2(g), \; \Delta H = -361.0\text{kJ} \] ii. \[ \text{NO}(g) + \frac{1}{2}\text{O}_2(g) \rightarrow \text{NO}_2(g), \; \Delta H = -57.06 \text{kJ} \]
Transcribed Image Text:**Heat of Combustion: Application of Hess's Law Pre-Lab** 1. Find ΔH for the reaction: \[ \text{N}_2(g) + 2\text{O}_2(g) \rightarrow 2\text{NO}_2(g) \] Given: i. \[ 4\text{NO}(g) + 2\text{O}_2(g) \rightarrow 2\text{N}_2(g) + 2\text{NO}_2(g), \; \Delta H = -361.0\text{kJ} \] ii. \[ \text{NO}(g) + \frac{1}{2}\text{O}_2(g) \rightarrow \text{NO}_2(g), \; \Delta H = -57.06 \text{kJ} \]
Expert Solution
Step 1

According to Hess's law, 

The enthalpy change of reaction sum of intermediate reactions•

N2(g) + 2O2(g) ----> 2NO2(g)   ------(iii) 

From reaction (i) & (ii) 

Rxn(iii) = [rxn(i) - 4×rxn(ii) ]/2

□H3 = [□H1 - 4×□H2]/2

    = [ -361 + 4 × 57.06]/2

  = -66.4 kJ

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