8. How many moles are in 16.4g of Lead (II) nitrate? Pb(NO3)2 + 2KI → Pbl2 + 2KNO3 9. How many moles of lead (II) iodide are formed from your moles of lead (II) nitrate in question 8? Pb(NO3)2 + 2KI → PbI2 + 2KNO3 10. How many grams are there in your moles of lead (II) iodide from question 9?
8. How many moles are in 16.4g of Lead (II) nitrate? Pb(NO3)2 + 2KI → Pbl2 + 2KNO3 9. How many moles of lead (II) iodide are formed from your moles of lead (II) nitrate in question 8? Pb(NO3)2 + 2KI → PbI2 + 2KNO3 10. How many grams are there in your moles of lead (II) iodide from question 9?
Chemistry
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Chapter1: Chemical Foundations
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A
B
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Pb(NO3)2 + 2KI → Pbl, + 2KNO3
11. How many moles are in 28.5g of potassium iodide?
Pb(NO3)2 + 2KI → PbI2 + 2KNO3
12. How many moles of lead (II) iodide are formed from your moles of potassium iodide in
question 11?
2
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Pb(NO3)2 + 2KI → PbI, + 2KNO3
13. How many grams are in there in your moles of lead (II) iodide in question 12?
Pb(NO3)2 + 2KI → PbI2 + 2KNO3
14. Which compound is your limiting reactant lead (II) nitrate or potassium iodide? (Hint: which
produced less product)
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O Editing v
s New Ro.. v 12
A
B
I
U
Ev Ev E E E A-
Pb(NO3)2 + 2KI → Pbl, + 2KNO3
11. How many moles are in 28.5g of potassium iodide?
Pb(NO3)2 + 2KI → PbI2 + 2KNO3
12. How many moles of lead (II) iodide are formed from your moles of potassium iodide in
question 11?
2
I
Hea
Pb(NO3)2 + 2KI → PbI, + 2KNO3
13. How many grams are in there in your moles of lead (II) iodide in question 12?
Pb(NO3)2 + 2KI → PbI2 + 2KNO3
14. Which compound is your limiting reactant lead (II) nitrate or potassium iodide? (Hint: which
produced less product)
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3Ba+ N2 → BazN2
7. Which element is your limiting reactant Barium or Nitride? (Hint: which produced less
product)
Pb(NO3)2 + 2KI → PbI, + 2KNO3
8. How many moles are in 16.4g of Lead (II) nitrate?
Pb(NO3)2 + 2KI → PbI2 + 2KNO3
9. How many moles of lead (II) iodide are formed from your moles of lead (II) nitrate in
question 8?
Pb(NO3)2 + 2KI → PbI, + 2KNO3
10. How many grams are there in your moles of lead (II) iodide from question 9?
Pb(NO3)2 + 2KI → PbI2 + 2KNO3
11. How many moles are in 28.5g of potassium iodide?
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O Editing v
w Ro... v 12
A^
U
ev Av A
=<而< 向 川<
3Ba+ N2 → BazN2
7. Which element is your limiting reactant Barium or Nitride? (Hint: which produced less
product)
Pb(NO3)2 + 2KI → PbI, + 2KNO3
8. How many moles are in 16.4g of Lead (II) nitrate?
Pb(NO3)2 + 2KI → PbI2 + 2KNO3
9. How many moles of lead (II) iodide are formed from your moles of lead (II) nitrate in
question 8?
Pb(NO3)2 + 2KI → PbI, + 2KNO3
10. How many grams are there in your moles of lead (II) iodide from question 9?
Pb(NO3)2 + 2KI → PbI2 + 2KNO3
11. How many moles are in 28.5g of potassium iodide?
909
U.S.)
Text Predictions: On
ASUS
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