Part B What Celsius temperature, T₂, is required to change the volume of the gas sample in Part A (T₁ = 14 °C, V₁= 1.88x103 L) to a volume of 3.76x103 L? Assume no change in pressure or the amount of gas in the balloon. Express your answer with the appropriate units. ▸ View Available Hint(s) μA ?

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**Educational Resource: Understanding Charles's Law**

---

### Topic: Temperature and Volume

**Charles's Law** states that the volume of a gas is directly related to its absolute temperature, provided there is no change in the pressure or amount of gas. This is expressed mathematically as:

\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \]

---

### Figure Description

Two diagrams illustrate the relationship between temperature and gas volume:

1. **Left Diagram:** 
   - A container with gas particles at a **lower temperature**, resulting in a **smaller volume**.
   - The particles are shown in blue with less spacing between them.
   - A flame is shown beneath the container indicating heat.

2. **Right Diagram:**
   - A container with gas particles at a **higher temperature**, leading to a **larger volume**.
   - The particles have more space between them, indicated by their dispersion.
   - A larger flame is depicted, indicating increased heat input.

---

### Practice Problem

**Part B:**

Determine the Celsius temperature \( T_2 \) needed to alter the volume of a gas sample from a starting condition:

- Initial Temperature \( T_1 = 14^\circ C \)
- Initial Volume \( V_1 = 1.88 \times 10^3 \, L \)

To a final volume of:

- \( V_2 = 3.76 \times 10^3 \, L \)

Assume no change in pressure or gas amount. Use appropriate units for the answer.

**Input Attempt:**
- Entered Value: \( T_2 = 289^\circ C \)
- Note: The input was incorrect, indicated by a prompt to "Try Again," with 2 attempts remaining.

---

Please use this information to further understand the application of Charles's Law in thermodynamics.
Transcribed Image Text:**Educational Resource: Understanding Charles's Law** --- ### Topic: Temperature and Volume **Charles's Law** states that the volume of a gas is directly related to its absolute temperature, provided there is no change in the pressure or amount of gas. This is expressed mathematically as: \[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \] --- ### Figure Description Two diagrams illustrate the relationship between temperature and gas volume: 1. **Left Diagram:** - A container with gas particles at a **lower temperature**, resulting in a **smaller volume**. - The particles are shown in blue with less spacing between them. - A flame is shown beneath the container indicating heat. 2. **Right Diagram:** - A container with gas particles at a **higher temperature**, leading to a **larger volume**. - The particles have more space between them, indicated by their dispersion. - A larger flame is depicted, indicating increased heat input. --- ### Practice Problem **Part B:** Determine the Celsius temperature \( T_2 \) needed to alter the volume of a gas sample from a starting condition: - Initial Temperature \( T_1 = 14^\circ C \) - Initial Volume \( V_1 = 1.88 \times 10^3 \, L \) To a final volume of: - \( V_2 = 3.76 \times 10^3 \, L \) Assume no change in pressure or gas amount. Use appropriate units for the answer. **Input Attempt:** - Entered Value: \( T_2 = 289^\circ C \) - Note: The input was incorrect, indicated by a prompt to "Try Again," with 2 attempts remaining. --- Please use this information to further understand the application of Charles's Law in thermodynamics.
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