2. Determine the total volume of all gases (at STP) formed when 50.0 mL of TNT (C3H5(NO3)3, density = 1.60 g/mL, molar mass = 227.10 g/mol) reacts according to the following reaction. 4 C3H5(NO3)3(1)→ 6 N₂(g) + O2(g) + 12 CO₂(g) + 10 H₂O(g)
2. Determine the total volume of all gases (at STP) formed when 50.0 mL of TNT (C3H5(NO3)3, density = 1.60 g/mL, molar mass = 227.10 g/mol) reacts according to the following reaction. 4 C3H5(NO3)3(1)→ 6 N₂(g) + O2(g) + 12 CO₂(g) + 10 H₂O(g)
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![2. Determine the total volume of all gases (at STP) formed when 50.0 mL of TNT (C₃H₅(NO₃)₃, density = 1.60 g/mL, molar mass = 227.10 g/mol) reacts according to the following reaction.
\[ 4 \, \text{C}_3\text{H}_5(\text{NO}_3)_3 (\text{l}) \rightarrow 6 \, \text{N}_2 (\text{g}) + \text{O}_2 (\text{g}) + 12 \, \text{CO}_2 (\text{g}) + 10 \, \text{H}_2\text{O} (\text{g}) \]
**Explanation:**
- This problem involves calculating the total volume of gases produced at standard temperature and pressure (STP) from a specified volume of liquid TNT.
- TNT's chemical formula is C₃H₅(NO₃)₃, with a given density and molar mass.
- The balanced chemical equation describes the decomposition of TNT into nitrogen gas (N₂), oxygen gas (O₂), carbon dioxide gas (CO₂), and water vapor (H₂O).
- At STP, one mole of any ideal gas occupies 22.4 liters. This principle will be used to calculate the total gas volume after the reaction.
No graphs or diagrams are present in the given image.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9b27e901-e87b-4228-8406-e843591659e6%2F4a30e94c-9fe0-4881-bde7-74e088409baa%2Ftlin7cl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. Determine the total volume of all gases (at STP) formed when 50.0 mL of TNT (C₃H₅(NO₃)₃, density = 1.60 g/mL, molar mass = 227.10 g/mol) reacts according to the following reaction.
\[ 4 \, \text{C}_3\text{H}_5(\text{NO}_3)_3 (\text{l}) \rightarrow 6 \, \text{N}_2 (\text{g}) + \text{O}_2 (\text{g}) + 12 \, \text{CO}_2 (\text{g}) + 10 \, \text{H}_2\text{O} (\text{g}) \]
**Explanation:**
- This problem involves calculating the total volume of gases produced at standard temperature and pressure (STP) from a specified volume of liquid TNT.
- TNT's chemical formula is C₃H₅(NO₃)₃, with a given density and molar mass.
- The balanced chemical equation describes the decomposition of TNT into nitrogen gas (N₂), oxygen gas (O₂), carbon dioxide gas (CO₂), and water vapor (H₂O).
- At STP, one mole of any ideal gas occupies 22.4 liters. This principle will be used to calculate the total gas volume after the reaction.
No graphs or diagrams are present in the given image.
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