Part B involves the addition of sodium acetate in the reaction between 2.6- dimethylaniline and chloroacetyl chloride. Why is sodium acetate used in this step? ○ To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a stronger nucleophile so less reactive O To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a weaker nucleophile so less reactive To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a stronger nucleophile so more reactive O To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a weaker nucleophile so more reactive

Part B involves the addition of sodium acetate in the reaction between 2.6- dimethylaniline and chloroacetyl chloride. Why is sodium acetate used in this step? ○ To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a stronger nucleophile so less reactive O To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a weaker nucleophile so less reactive To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a stronger nucleophile so more reactive O To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a weaker nucleophile so more reactive

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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