PART : APPLICATION OP EQUATIONS OF BQUHBRIUM(SOLYE FOR THE VALUES OF THE UNKNOON VARIABIES)PROBUEM A :GNEN :R= 6.25 KNPa - 2.75 KNPg- 3.72 KNM = 3.42 KN mW,- SKH/M3 56 KN/MW.BUNKNOWNS :O KAy , RBy RBXO VALUE OF SHEAR 4.om TO THE RI6HTOF supPOR A2. SM1Mim

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PART : APPuICATION OP EQUATIONS OF BRUHBRIUM (SOLYE FOR THE VALUES OF THE UNKNOON VARIABIES) PROBUEM A : GNEN : R= 6.25 KN P2 - 2.75 KN M = 3.42 KN m W,- SKH/M P = ও.72 A 3 56 KH/M W. B UNKNOWNS : O KAy , RBy RBX O VALUE OF SHEAR 4.om TO THE RI6HT OF SUPPORA 2. SM im

PART : APPuICATION OP EQUATIONS OF BRUHBRIUM (SOLYE FOR THE VALUES OF THE UNKNOON VARIABIES) PROBUEM A : GNEN : R= 6.25 KN P2 - 2.75 KN M = 3.42 KN m W,- SKH/M P = ও.72 A 3 56 KH/M W. B UNKNOWNS : O KAy , RBy RBX O VALUE OF SHEAR 4.om TO THE RI6HT OF SUPPORA 2. SM im

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Test for Determination of Shear Strength

The term shear strength is often associated with the soil. Shear strength is defined as the resistance to the deformation of soil particles due to the continuous action of shear stress. In short, shear strength is the maximum shear stress that a soil can sustain.

Question

PART : APPLICATION OP EQUATIONS OF BQUHBRIUM
(SOLYE FOR THE VALUES OF THE UNKNOON VARIABIES)
PROBUEM A :
GNEN :
R= 6.25 KN
Pa - 2.75 KN
Pg- 3.72 KN
M = 3.42 KN m
W,- SKH/M
3 56 KN/M
W.
B
UNKNOWNS :
O KAy , RBy RBX
O VALUE OF SHEAR 4.om TO THE RI6HT
OF supPOR A
2. SM
1M
im

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