PART : APPLICATION OP EQUATIONS OF BQUHBRIUM(SOLYE FOR THE VALUES OF THE UNKNOWON VARIABUES)PROBUEM A :GNEN :WiR = 6.25 KNP2 2.75 KNPg- 3.72 KNM = 3.42 KN . Mw,- SKH/MWz. 3 56 KN/mM.UNKNOWNS :O RAy, RBy & RBXO VALUE OF SHEAR 4.0M TO THE RIGHTOF SUPPOR A2mPROBEM B:PzGIVENUNINOWNSR = 1.39 KNPze 6.05 KNWi= 4KN/m@ RAY, RBY, keA & MBFHEDVALUE OF INERNALMOMENT 2m to THELEFT OF SUPPORT BRCLLERIm Im2.50mPROBUEM C :6NENUNKNOWNSR= 6.8S KHP2- 4.65KNW, = 6.15 10/mO KAY , RA*Rey, 오 mA|P2O WHAT IS THE VALUE of INTERNALSHEAR 2.53m to THE KI6HTOf suPpOreT A1.75m1.95A2.25Mo ROUERY FIYEDPROBIEM PZNENW;- SKN/mWz > 1OKN/MPzAA = l0 KHWiO UN KNOWNS ! RAY, RBy, Rex & MBO compUTE THE INTERNAL SHEAR1.75 m TO THE RI6HT OF SUPPORT A2.5m2 SM

Since, the problem number to be solved is not stated, the solution for Question A is as follows: The…

Answered: PROBUEM A : ENEN : R= 6.25 KN M = 3.42…

PROBUEM A : ENEN : R= 6.25 KN M = 3.42 KN m w,- SKA/M P2. 2.75 KN Pg= 3.72 KN UNKNOWNS : O RAy, RBy & RBX @ VALUE OF SHEAR 4.0 M TO THE RIGHT OF SUPPOR A 2m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

PART : APPLICATION OP EQUATIONS OF BQUHBRIUM
(SOLYE FOR THE VALUES OF THE UNKNOWON VARIABUES)
PROBUEM A :
GNEN :
Wi
R = 6.25 KN
P2 2.75 KN
Pg- 3.72 KN
M = 3.42 KN . M
w,- SKH/M
Wz. 3 56 KN/m
M.
UNKNOWNS :
O RAy, RBy & RBX
O VALUE OF SHEAR 4.0M TO THE RIGHT
OF SUPPOR A
2m
PROBEM B:
Pz
GIVEN
UNINOWNS
R = 1.39 KN
Pze 6.05 KN
Wi= 4KN/m
@ RAY, RBY, keA & MB
FHED
VALUE OF INERNAL
MOMENT 2m to THE
LEFT OF SUPPORT B
RCLLER
Im Im
2.50m
PROBUEM C :
6NEN
UNKNOWNS
R= 6.8S KH
P2- 4.65KN
W, = 6.15 10/m
O KAY , RA*
Rey, 오 mA
|P2
O WHAT IS THE VALUE of INTERNAL
SHEAR 2.53m to THE KI6HT
Of suPpOreT A
1.75m
1.95A
2.25M
o ROUER
Y FIYED
PROBIEM P
ZNEN
W;- SKN/m
Wz > 1OKN/M
Pz
A
A = l0 KH
Wi
O UN KNOWNS ! RAY, RBy, Rex & MB
O compUTE THE INTERNAL SHEAR
1.75 m TO THE RI6HT OF SUPPORT A
2.5m
2 SM

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